We are not given a value of P in this problem, so either pick a value
for P and stick with that throughout the problem, or just let P = P.
We have that t = 1, and r = .055. To find the effective rate of interest,
first find out how much money we have after one year:
A = Pert
A = Pe(.055)(1)
A = 1.056541P.
Therefore, after 1 year, whatever the principal was, we now have 1.056541P.
Next, find out how much interest was earned, I, by subtracting the initial amount of money from the final amount:
I = A ? P
= 1.056541P ? P
= .056541P.
Finally, to find the effective rate of interest, use the simple interest formula, I = Prt. So,
I = Pr(1) = .056541P
.056541 = r.
Therefore, the effective rate of interest is 5.65%
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
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