Rs.1440 - 1200 = Rs.240 is the interest on Rs.1200 for one year.
Rate of interest = (100 x 240) / (1200) = 20% p.a
Let p = Rs. 100.
Then, S.I is Rs. 50 and time = 5 years.
= 10% p.a.
Now, p = Rs. 12,000 , T = 3 years and R = 10% p.a.
C.I. = Rs.
= Rs. 3972
Amount
= Rs[7500x(1+4/100)²]
=Rs.(7500 * 26/25 * 26/25)
=Rs.8112
C.I
= Rs(8112 - 7500)
=Rs.612
C.I. =Rs[4000x(1+10/100)²-4000]
Rs.(4000x11/10x11/10-4000) = Rs.940.
Sum
=Rs. [420 *100 /3 * 8]
= Rs.1750.
Principal = Rs.1000;
Amount = Rs.1331;
Rate = Rs.10%p.a.
Let the time be n years.Then
[1000(1+10/100)?n;]
= 1331.
= (1331/1000)
= (11/10)³
Therefore n = 3 years.
j=mi
I = ptr
Therefore, the total amount the owner received on January 17, 2001 was
$1295.57 + $10.47 = $1306.04
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