I. gives, Rate = 5% p.a.
II. gives, S.I. for 1 year = Rs. 600.
III. gives, sum = 10 x (S.I. for 2 years).
Now I, and II give the sum.
For this sum, C.I. and hence amount can be obtained.
Thus, III is redundant.
Again, II gives S.I. for 2 years = Rs. (600 x 2) = Rs. 1200.
Now, from III, Sum = Rs. (10 x 1200) = Rs . 12000.
Thus,Rate = =5%
Thus, C.I. for 2 years and therefore, amount can be obtained.
Thus, I is redundant.
The usual way to find the compound interest is given by the formula A = .p(1+r/100)^n
In this formula,
A is the amount at the end of the period of investment
P is the principal that is invested
r is the rate of interest in % p.a
And n is the number of years for which the principal has been invested.
In this case, it would turn out to be A =1500(1+20/100)^3
= 2592.
Shawn received an extra amount of (Rs.605 ? Rs.550) Rs.55 on his compound interest paying bond as the interest that he received in the first year also earned interest in the second year.
The extra interest earned on the compound interest bond = Rs.55
The interest for the first year =550/2 = Rs.275
Therefore, the rate of interest = = 20% p.a.
20% interest means that Shawn received 20% of the amount he invested in the bonds as interest.
If 20% of his investment in one of the bonds = Rs.275, then his total investment in each of the bonds = = 1375.
As he invested equal sums in both the bonds, his total savings before investing = 2 x 1375 =Rs.2750.
At first glance it might seem that this problem cannot be solved because we do not have enough
information. It can be solved as long as you double whatever amount you start with. If we start with
$100, then P = $100 and FV = $200.
FV=P(1+r/n)^nt
Given,
Compound rate, R = 10% per annum
Time = 2 years
C.I = Rs. 420
Let P be the required principal.
A = (P+C.I)
Amount, A =
(P+C.I) =
(P+420) = P[11/10][11/10]
P-1.21P = -420
0.21P = 420
Hence, P = 420/0.21 = Rs. 2000
Amount =
= 8000 x 21/20 x 21/20
= Rs. 8820
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.