Given compound interest for 3 years = Rs. 1513.2
and simple interest for 5 years = Rs. 2400
Now, we know that C.I =
=> 1513.2 = ...........(A)
And S.I = PTR/100
=> 2400 = P5R/100 ..................(B)
By solving (A) & (B), we get
R = 5%.
Compound Interest for 1 1?2 years when interest is compounded yearly = Rs.(5304 - 5000)
Amount after 11?2 years when interest is compounded half-yearly
Compound Interest for 1 1?2 years when interest is compounded half-yearly = Rs.(5306.04 - 5000)
Difference in the compound interests = (5306.04 - 5000) - (5304 - 5000)= 5306.04 - 5304 = Rs. 2.04
8000 × 33.1% = 2648
Let Rs. K invested in each scheme
Two years C.I on 20% = 20 + 20 + 20x20/100 = 44%
Two years C.I on 15% = 15 + 15 + 15x15/100 = 32.25%
Now,
(P x 44/100) - (P x 32.25/100) = 528.75
=> 11.75 P = 52875
=> P = Rs. 4500
Hence, total invested money = P + P = 4500 + 4500 = Rs. 9000.
Let 'R%' be the rate of interest
From the given data,
Hence, the rate of interest R = 5% per annum.
We know the formula for calculating
The compound interest where P = amount, r = rate of interest, n = time
Here P = 5000, r1 = 10, r2 = 20
Then
C = Rs. 4826.
Amount
= Rs.(25000x(1+12/100)³
= Rs.(25000x28/25x28/25x28/25)
= Rs. 35123.20.
C.I = Rs(35123.20 -25000)
= Rs.10123.20
Shyam's share * (1+0.05)9 = Ram's share * (1 + 0.05)11
Shyam's share / Ram's share = (1 + 0.05)11 / (1+ 0.05)9 = (1+ 0.05)2 = 441/400
Therefore Shyam's share = (441/841) * 5887 = 3087
Let the rate be R% p.a. Then,
Rate = 15%.
sum=Rs.x
C.I=[x(1+4/100)^2-x]=(676/625x-x)=51/625
S.I=(x*4*2)/100=2x/25
x=625
Let the sum be Rs. x. Then,
C.I. = x ( 1 + ( 10 /100 ))^2 - x = 21x / 100 ,
S.I. = (( x * 10 * 2) / 100) = x / 5
(C.I) - (S.I) = ((21x / 100 ) - (x / 5 )) = x / 100
( x / 100 ) = 632 * x = 63100.
Hence, the sum is Rs.63,100.
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