Interest earned in scheme M =
Interest earned in scheme N =
Now, from the given data,
k = 11
principal =
= Rs.4096
Let the two parts be Rs. x and Rs. (1301 - x).
=> 625x=676(1301-x)
1301x=676 x 1301x=676.
So,the parts are rs.676 and rs.(1301-676)i.e rs.676 and rs.625
The population grew from 3600 to 4800 in 3 years. That is a growth of 1200 on 3600 during three year span.
Therefore, the rate of growth for three years has been constant.
The rate of growth during the next three years will also be the same.
Therefore, the population will grow from 4800 by = 1600
Hence, the population three years from now will be 4800 + 1600 = 6400
Present Worth
=
=
= Rs.156.25
C.I.= Rs.[4000*(1+10/100)^2-4000]
=Rs.840
sum=Rs.(420 * 100)/3*8=Rs.1750
We know the formula for calculating
The compound interest where P = amount, r = rate of interest, n = time
Here P = 5000, r1 = 10, r2 = 20
Then
C = Rs. 4826.
Let 'R%' be the rate of interest
From the given data,
Hence, the rate of interest R = 5% per annum.
Let Rs. K invested in each scheme
Two years C.I on 20% = 20 + 20 + 20x20/100 = 44%
Two years C.I on 15% = 15 + 15 + 15x15/100 = 32.25%
Now,
(P x 44/100) - (P x 32.25/100) = 528.75
=> 11.75 P = 52875
=> P = Rs. 4500
Hence, total invested money = P + P = 4500 + 4500 = Rs. 9000.
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