Amount = Rs [7500*(1+(4/100)2] = Rs (7500 * (26/25) * (26/25) ) = Rs. 8112.
therefore, C.I. = Rs. (8112 - 7500) = Rs. 612.
S.I
= Rs.(1200x10x1/100)
= Rs.120.
C.I
= Rs[(1200x1+5/100)² -1200]
= Rs.123.
Difference
= Rs.[123-120]
= Rs. 3.
We know thatThe Difference between Compound Interest and Simple Interest for n years at R rate of interest is given by
Here n = 2 years, R = 20%, C.I - S.I = 56
Difference in C.I and S.I for 2 years
= Rs(696.30-660)
=Rs. 36.30.
S.I for one years = Rs330.
S.I on Rs.330 for 1 year =Rs. 36.30
Rate
= (100x36.30/330x1)%
= 11%
Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
R= =10% p.a
Now, P = Rs. 12000. T = 3 years and R = 10% p.a.
C.I=
=Rs.3972
Principal = Rs. 1000; Amount = Rs. 1331; Rate = 10% p.a. Let the time be n years. Then,
[ 1000 (1+ (10/100))^n ] = 1331 or (11/10)^n = (1331/1000) = (11/10)^3
n = 3 years
The population grew from 3600 to 4800 in 3 years. That is a growth of 1200 on 3600 during three year span.
Therefore, the rate of growth for three years has been constant.
The rate of growth during the next three years will also be the same.
Therefore, the population will grow from 4800 by = 1600
Hence, the population three years from now will be 4800 + 1600 = 6400
Let the two parts be Rs. x and Rs. (1301 - x).
=> 625x=676(1301-x)
1301x=676 x 1301x=676.
So,the parts are rs.676 and rs.(1301-676)i.e rs.676 and rs.625
principal =
= Rs.4096
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.