(2 x 14) men +(7 x 14) boys = (3 x 11) men + (8 x 11) boys
=>5 men= 10 boys => 1man= 2 boys
Therefore, (2 men+ 7 boys) = (2 x 2 +7) boys = 11 boys
( 8 men + 6 boys) = (8 x 2 +6) boys = 22 boys.
Let the required number of days be x.
More boys , Less days (Indirect proportion)
More work , More days (Direct proportion)
Therefore, (22 * 1 * x) = (11 * 3 * 14)
=> x = 21
Hence, the required number of days = 21
Let, Ages of Vijaya and Simran ? 1 year ago was 4A and A years correspondingly.
Then, [(4A + 1) + 6] ? [(A + 1) + 6] = 9
3A = 9 => A = 3
Needed Ratio = (4A + 1) : (A + 1) = 13 : 4
Let the two item be A and B.
Cost price of A be x and cost price of B be y.
A sold for Rs 1000 on 10 % gain = 1.1x =1000
x= 1000/1.1 = 909.09
B sold for Rs. 1000 on 10% loss = 0.9y =1000y= 1000/0.9 = 1111.11
Total cost price of A and B = 2020.20
Selling price of A and B = 2000
Loss % = (2020.20 ?2000)/2000 X 100
= 1.01 % loss
Given R + S + M + D = 76
=> R+7 : S+7 : M+7 : D+7 = 7:6:5:8
=> Let the ratio = x
=> M+7 = 5x
=> M = 5x-7
=> R = 7x-7
=> S = 6x-7
=> D = 8x-7
=> R + S + M + D = 76
=> 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76
=> 26x - 28 = 76
=> 26x = 104
=> x = 4
=> Mahesh's present age = 5x-7 = 20 - 7 = 13 years.
Let CP be x and SP be y.
3(y ?x) = (2y ?x)y = 2x
Profit = y ?x = 2x ?x = x
Profit% = x/x X 100 = 100%
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