Originally let there be x men.
Less men, More days (Indirect Proportion)
Therefore, (x-10) : x :: 100 :110
=> (x - 10) * 110 = x * 100 => x= 110
Let the required length be x meters
More men, More length built (Direct proportion)
Less days, Less length built (Direct Proportion)
=> (20 x 6 x X)=(35 x 3 x 56)
=> x = 49
Hence, the required length is 49 m.
Let the required no of hours be x. Then
Less men , More hours (Indirct Proportion)
Therefore, 15:36 ::25:x
=> (15 x X)=(36 x 25) => x = 60
Hence, 15 men can do it in 60 hours.
(2 x 14) men +(7 x 14) boys = (3 x 11) men + (8 x 11) boys
=>5 men= 10 boys => 1man= 2 boys
Therefore, (2 men+ 7 boys) = (2 x 2 +7) boys = 11 boys
( 8 men + 6 boys) = (8 x 2 +6) boys = 22 boys.
Let the required number of days be x.
More boys , Less days (Indirect proportion)
More work , More days (Direct proportion)
Therefore, (22 * 1 * x) = (11 * 3 * 14)
=> x = 21
Hence, the required number of days = 21
Let the required number days be x.
Less spiders, More days (Indirect Proportion)
Less webs, Less days (Direct Proportion)
=> 1 * 7 * x = 7 * 1 * 7
=> x= 7
[(100 x 35) + (200 x 5)]men can finish the work in 1 day
Therefore, 4500 men can finish the work in 1 day. 100 men can finish it in 4500/100= 45 days.
This is 5 days behind Schedule
Let the required number of days be x.
Less persons, More days (Indirect Proportion)
More working hours per day, Less days (Indirect Proportion)
=> 30 * 6 * x = 39 * 5 * 12
=> x= 13
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