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- Question
Karan remembers that his sister's birthday is not after 18th August. Karan's mother remembers that Karan's sister birthday is before 20th August but after 17th August. On which date of August is Karan's sister birthday?
Options- A. 18
- B. 17
- C. 19
- D. 20
- Correct Answer
- 18
- 1. What was the day on 31st Dec,2011 ?
Options- A. Monday
- B. Saturday
- C. Sunday
- D. Friday Discuss
- 2. Which of the following year is a leap year?
Options- A. 2500
- B. 1700
- C. 1900
- D. 2400 Discuss
- 3. The calendar of the year 2006 was used before in the year?
Options- A. 1990
- B. 1995
- C. 2002
- D. 2000 Discuss
- 4. If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Options- A. Tuesday
- B. Wednesday
- C. Sunday
- D. Friday Discuss
- 5. The last day of a century cannot be
Options- A. Monday
- B. Wednesday
- C. Tuesday
- D. Friday Discuss
- 6. If 1st January 2013 was Wednesday, then what day of the week was it on 2nd January 2014?
Options- A. Wednesday
- B. Thursday
- C. Tuesday
- D. Friday Discuss
- 7. Divyansh's birthday is on Sunday 16th July. On what day of the week will be Shaan's Birthday in the same year if Shaan was born on 1st August?
Options- A. Tuesday
- B. Monday
- C. Wednesday
- D. Sunday Discuss
- 8. Gurkiran's birthday is on Sunday 21st May. On what day of the week will be Shreyas's Birthday in the same year if Shreyas was born on 14th November?
Options- A. Tuesday
- B. Wednesday
- C. Friday
- D. Saturday Discuss
- 9. Chirag's birthday is on Thursday 1st June. On what day of the week will be Reyansh's Birthday in the same year if Reyansh was born on 3rd December?
Options- A. Wednesday
- B. Sunday
- C. Friday
- D. Saturday Discuss
- 10. Mishti's birthday is on Thursday 27th April. On what day of the week will be Aradhya's Birthday in the same year, if Aradhya was born on 20th October?
Options- A. Friday
- B. Wednesday
- C. Saturday
- D. Thursday Discuss
Calendar problems
Search Results
Correct Answer: Saturday
Explanation:
31st Dec, 2011 = (2010 years + Period from 1.1.2011 to 31.12.2011)
Odd days in 2000 years = 0
10 years has 2 leap years + 8 ordinary years.
Number of odd days in 10 years ( 2 x 2 + 8) = 5 odd days.
31st,Dec => complete year of 2011 (non-leap year) = 1 odd day.
Total number of odd days = (0 + 5 + 1) = 6.
Given day is saturday.
Correct Answer: 2400
Explanation:
NOTE: For a century year,it is divided by 400 and leaving a ramainder of 0 results a leap year.
So,2400 when divided by 400 leaves a remainder 0.
Correct Answer: 1995
Explanation:
Given year 2006, when divided by 4 leaves a remainder of 2.
NOTE: When remainder is 2, 11 is subtracted to the given year to get the result.
So, 2006 - 11 = 1995
Correct Answer: Sunday
Explanation:
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005.
So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
Correct Answer: Tuesday
Correct Answer: Friday
Correct Answer: Tuesday
Correct Answer: Tuesday
Correct Answer: Sunday
Correct Answer: Friday
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