As we know that a week has 7 days,
k weeks k days = (7k + k) days = 8k days.
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday
1 Oct, 1994 = (1993 years + Period from 1.1.1993 to 1.10.1993)
Odd days in 1600 years = 0
Odd days in 300 years = 1
93 years = (70 ordinary years + 23 leap year) = (70 x 1 + 23 x 2)= 4 odd days
Jan Feb March April May June July Aug sept Oct
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 1 ) = 274 days
274 days = (39 weeks + 1 day) =1 odd day.
Total number of odd days = (0 + 1 + 4 + 1) = 6 odd days.
Given day is Saturday.
25 Jan, 1981 = (1980 years + Period from 1.1.1981 to 25.1.1981)
Odd days in 1600 years = 0
Odd days in 300 years = 1
80 years = (60 ordinary years + 20 leap year) = (60 x 1 + 20 x 2)= 2 odd days
Jan = 25 days = (3 weeks + 4 days) = 4 odd days.
Total number of odd days = (0 + 1 + 2 + 4) = 7= 0 odd day.
Given day is Sunday.
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005.
So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
Given year 2006, when divided by 4 leaves a remainder of 2.
NOTE: When remainder is 2, 11 is subtracted to the given year to get the result.
So, 2006 - 11 = 1995
NOTE: For a century year,it is divided by 400 and leaving a ramainder of 0 results a leap year.
So,2400 when divided by 400 leaves a remainder 0.
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