1 Oct, 1994 = (1993 years + Period from 1.1.1993 to 1.10.1993)
Odd days in 1600 years = 0
Odd days in 300 years = 1
93 years = (70 ordinary years + 23 leap year) = (70 x 1 + 23 x 2)= 4 odd days
Jan Feb March April May June July Aug sept Oct
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 1 ) = 274 days
274 days = (39 weeks + 1 day) =1 odd day.
Total number of odd days = (0 + 1 + 4 + 1) = 6 odd days.
Given day is Saturday.
25 Jan, 1981 = (1980 years + Period from 1.1.1981 to 25.1.1981)
Odd days in 1600 years = 0
Odd days in 300 years = 1
80 years = (60 ordinary years + 20 leap year) = (60 x 1 + 20 x 2)= 2 odd days
Jan = 25 days = (3 weeks + 4 days) = 4 odd days.
Total number of odd days = (0 + 1 + 2 + 4) = 7= 0 odd day.
Given day is Sunday.
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
therfore, on 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday
NOTE: For an century year,it is divided by 400,when leaves a remainder 0 then it is a leap year.
So, 1600
NOTE: When an year leaves a remainder 0 when divided by 4,then it is a leap year.
Here, 1984 divided by 4 leaves a remainder 0.
So, answer 1984 (366 days => leap year)
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday
As we know that a week has 7 days,
k weeks k days = (7k + k) days = 8k days.
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