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- Question
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Options- A. Sunday
- B. Saturday
- C. Friday
- D. Wednesday
- Correct Answer
- Friday
ExplanationOn 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
therfore, on 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday
- 1. Which century year is a leap year?
Options- A. 1900
- B. 1700
- C. 1600
- D. 1100 Discuss
- 2. Which of the following years have 366 days?
Options- A. 1984
- B. 1863
- C. 1900
- D. 2500 Discuss
- 3. Which calendar was used again in the year 1856?
Options- A. 1828
- B. 1850
- C. 1830
- D. 1852 Discuss
- 4. The calendar for the year 2013 was the same as the year :
Options- A. 1998
- B. 2017
- C. 2009
- D. 2002 Discuss
- 5. If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Options- A. Sunday
- B. Saturday
- C. Tuesday
- D. Wednesday Discuss
- 6. On what dates of April, 2001 did Wednesday fall ?
Options- A. 1st, 8th, 15th, 22nd, 29th
- B. 2nd, 9th, 16th, 23rd, 30th
- C. 3rd, 10th, 17th, 24th
- D. 4th, 11th, 18th, 25th Discuss
- 7. What was the day on 25th Jan,1981?
Options- A. Monday
- B. Friday
- C. Sunday
- D. Tuesday Discuss
- 8. Oct 1st 1994 falls on which day?
Options- A. Sunday
- B. Saturday
- C. Friday
- D. Wednesday Discuss
- 9. What was the day of the week on 17th June, 1998?
Options- A. Wednesday
- B. Saturday
- C. Friday
- D. Tuesday Discuss
- 10. How many days are there in k weeks k days ?
Options- A. 8+k days
- B. 7+1k days
- C. 8k days
- D. 7/k days Discuss
Calendar problems
Search Results
Correct Answer: 1600
Explanation:
NOTE: For an century year,it is divided by 400,when leaves a remainder 0 then it is a leap year.
So, 1600
Correct Answer: 1984
Explanation:
NOTE: When an year leaves a remainder 0 when divided by 4,then it is a leap year.
Here, 1984 divided by 4 leaves a remainder 0.
So, answer 1984 (366 days => leap year)
Correct Answer: 1828
Explanation:
Given year 1856, when divided by 4 leaves a remainder of 0.
NOTE: When remainder is 0, 28 is subtracted to the given year to get the result.
So, 1856 - 28 = 1828
Correct Answer: 2002
Explanation:
Given year, 2013 when divided by 4 leaves a remainder of 1.
NOTE: When the remainder is 1, 11 is substracted from the given year to get the result.
So, 2013 - 11 =2002
Correct Answer: Sunday
Correct Answer: 4th, 11th, 18th, 25th
Correct Answer: Sunday
Explanation:
25 Jan, 1981 = (1980 years + Period from 1.1.1981 to 25.1.1981)
Odd days in 1600 years = 0
Odd days in 300 years = 1
80 years = (60 ordinary years + 20 leap year) = (60 x 1 + 20 x 2)= 2 odd days
Jan = 25 days = (3 weeks + 4 days) = 4 odd days.
Total number of odd days = (0 + 1 + 2 + 4) = 7= 0 odd day.
Given day is Sunday.
Correct Answer: Saturday
Explanation:
1 Oct, 1994 = (1993 years + Period from 1.1.1993 to 1.10.1993)
Odd days in 1600 years = 0
Odd days in 300 years = 1
93 years = (70 ordinary years + 23 leap year) = (70 x 1 + 23 x 2)= 4 odd days
Jan Feb March April May June July Aug sept Oct
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 1 ) = 274 days
274 days = (39 weeks + 1 day) =1 odd day.
Total number of odd days = (0 + 1 + 4 + 1) = 6 odd days.
Given day is Saturday.
Correct Answer: Wednesday
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday
Correct Answer: 8k days
Explanation:
As we know that a week has 7 days,
k weeks k days = (7k + k) days = 8k days.
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