Given year 1856, when divided by 4 leaves a remainder of 0.
NOTE: When remainder is 0, 28 is subtracted to the given year to get the result.
So, 1856 - 28 = 1828
Given year, 2013 when divided by 4 leaves a remainder of 1.
NOTE: When the remainder is 1, 11 is substracted from the given year to get the result.
So, 2013 - 11 =2002
The year 1985 is an ordinary year. So, it has 1 odd day.
So, the day on 19th June, 1985 will be 1 day after the day on 19th June, 1984.
But, 19th June,1984 is Monday
S0, 19th June, 1985 is Tuesday.
9th May, 2001 = (2000 years + Period from 1.1.2001 to 9.5.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 9) = 129 days
129 days = (18 weeks + 3 day)= 3 odd day.
Total number of odd days = (0 + 0 + 3 ) = 3 odd day.
Given day is Wednesday.
NOTE: When an year leaves a remainder 0 when divided by 4,then it is a leap year.
Here, 1984 divided by 4 leaves a remainder 0.
So, answer 1984 (366 days => leap year)
NOTE: For an century year,it is divided by 400,when leaves a remainder 0 then it is a leap year.
So, 1600
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
therfore, on 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday
25 Jan, 1981 = (1980 years + Period from 1.1.1981 to 25.1.1981)
Odd days in 1600 years = 0
Odd days in 300 years = 1
80 years = (60 ordinary years + 20 leap year) = (60 x 1 + 20 x 2)= 2 odd days
Jan = 25 days = (3 weeks + 4 days) = 4 odd days.
Total number of odd days = (0 + 1 + 2 + 4) = 7= 0 odd day.
Given day is Sunday.
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