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- Question
If 1st January 2013 was Tuesday, then what day of the week will be 31st December 2013?
Options- A. Wednesday
- B. Thursday
- C. Tuesday
- D. Monday
- Correct Answer
- Tuesday
- 1. What was the day on 16th June,1993?
Options- A. Saturday
- B. Monday
- C. Wednesday
- D. Friday Discuss
- 2. The calendar of year 1856 is same as which year?
Options- A. 1883
- B. 1884
- C. 1864
- D. 1880 Discuss
- 3. Kavya's birthday is on Tuesday 4th July. On what day of the week will be Anika's Birthday in the same year, if Anika was born on 15th August?
Options- A. Wednesday
- B. Friday
- C. Saturday
- D. Tuesday Discuss
- 4. The calendar for the year 2007 will be the same for the year ?
Options- A. 2014
- B. 2019
- C. 2021
- D. 2018 Discuss
- 5. In the year 2016, there were 52 weeks and P days. Find the value of P
Options- A. 2
- B. 4
- C. 3
- D. 5 Discuss
- 6. If 27th February 2011 was Sunday, then 1st March 2012 will be what day of the week?
Options- A. Thursday
- B. Friday
- C. Sunday
- D. Monday Discuss
- 7. Karan remembers that his sister's birthday is not after 18th August. Karan's mother remembers that Karan's sister birthday is before 20th August but after 17th August. On which date of August is Karan's sister birthday?
Options- A. 18
- B. 17
- C. 19
- D. 20 Discuss
- 8. Akshar remembers that the match is after 26th April but before 30th April, while Suresh remembers that the match is after 22nd April but before 28th April. On which date of April is the match?
Options- A. 29
- B. 26
- C. 27
- D. 28 Discuss
- 9. Aarush's birthday is on Thursday 27th April. On what day of the week will be Mitul's Birthday in the same year if Mitul was born on 28th September?
Options- A. Monday
- B. Thursday
- C. Wednesday
- D. Tuesday Discuss
- 10. Devansh's birthday is on Friday 14th April. On what day of the week will be Rohan's Birthday in the same year if Rohan was born on 20th September?
Options- A. Tuesday
- B. Friday
- C. Thursday
- D. Wednesday Discuss
Calendar problems
Search Results
Correct Answer: Wednesday
Explanation:
16 June, 1993 = (1992 years + Period from 1.1.1993 to 16.6.1993)
Odd days in 1600 years = 0
Odd days in 300 years = 1
92 years = (69 ordinary years + 23 leap year) = (69 x 1 + 23 x 2)= 3 odd days
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 16 ) = 167 days
167 days = (23 weeks + 6 days) =6 odd days.
Total number of odd days = (0 + 1 + 3 + 6) = 3 odd days.
Given day is Wednesday.
Correct Answer: 1884
Explanation:
Given year 1856, when divided by 4 leaves a remainder of 0.
NOTE: When remainder is 0, 28 is added to the given year to get the result.
So, 1856 + 28 = 1884
Correct Answer: Tuesday
Correct Answer: 2018
Explanation:
Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days => 0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
Correct Answer: 2
Correct Answer: Thursday
Correct Answer: 18
Correct Answer: 27
Correct Answer: Thursday
Correct Answer: Wednesday
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