Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days => 0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.
Here from 4th December 1999 to 3rd January 2000,
there is a difference of 30 days.
Number of odd days = 30/7 = 2 odd days
Then no. of odd days = 2 => tuesday and wednesday(from monday).
Hence on 3rd january it is wednesday.
18 Feb, 2016 = (2015 years + Period from 1.1.2016 to 18.2.2016)
Odd days in 1600 years = 0
Odd days in 400 years = 0
15 years = (12 ordinary years + 3 leap year) = (12 x 1 + 3 x 2)= 4 odd days
Jan Feb
(31 + 18 ) = 49 days
49 days = (7 weeks + 0 day)= 0 odd day.
Total number of odd days = (0 + 0 + 4 + 0) = 4 odd day.
Given day is Thursday
Given year 1856, when divided by 4 leaves a remainder of 0.
NOTE: When remainder is 0, 28 is added to the given year to get the result.
So, 1856 + 28 = 1884
16 June, 1993 = (1992 years + Period from 1.1.1993 to 16.6.1993)
Odd days in 1600 years = 0
Odd days in 300 years = 1
92 years = (69 ordinary years + 23 leap year) = (69 x 1 + 23 x 2)= 3 odd days
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 16 ) = 167 days
167 days = (23 weeks + 6 days) =6 odd days.
Total number of odd days = (0 + 1 + 3 + 6) = 3 odd days.
Given day is Wednesday.
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