The year 1985 is an ordinary year. So, it has 1 odd day.
So, the day on 19th June, 1985 will be 1 day after the day on 19th June, 1984.
But, 19th June,1984 is Monday
S0, 19th June, 1985 is Tuesday.
1.12.91 is the first Sunday of December 91.
So, 3.12.91 is the first Tuesday of the month.
Clearly, 10.12.91, 17.12.91, 24.12.91 and 31.12.91 are also Tuesdays.
So, 24.12.91 is the fourth Tuesday.
2nd Jan 1901 means
(1900 years and 2 day)
Now, 1600 years have 0 odd day
300 years have 1 odd day
2 days has 2 odd day
Total no. of odd days = 0 + 1 + 2 = 3 days
Hence, the day on 2nd Jan 1901 was Wednesday.
55 min. spaces are covered in 60 min.
60 min. spaces are covered in ((60/55) x 60) min = 720/11 min.
Loss in 65 min. = (720/11 - 65 ) = 5/11
Loss in 24 hrs = (5/11 x 1/65 x 24 x 60)min = 1440/143 min.
Given year 1939, when divided by 4 leaves a remainder of 3.
NOTE: When remainder is 3, 11 is added to the given year to get the result.
So, 1939 + 11 = 1950
18 Feb, 2016 = (2015 years + Period from 1.1.2016 to 18.2.2016)
Odd days in 1600 years = 0
Odd days in 400 years = 0
15 years = (12 ordinary years + 3 leap year) = (12 x 1 + 3 x 2)= 4 odd days
Jan Feb
(31 + 18 ) = 49 days
49 days = (7 weeks + 0 day)= 0 odd day.
Total number of odd days = (0 + 0 + 4 + 0) = 4 odd day.
Given day is Thursday
Here from 4th December 1999 to 3rd January 2000,
there is a difference of 30 days.
Number of odd days = 30/7 = 2 odd days
Then no. of odd days = 2 => tuesday and wednesday(from monday).
Hence on 3rd january it is wednesday.
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