Let the speed of boat in still water is ?x? km/hr & that of stream is ?y? km/hr.
Then, ATQ
(x+y)/y = 9/1 9y = x + y
x = 8y
y = 3 km/hr
So, x = 24 km/hr
Upstream speed = 24-3 = 21 km/hr
Hence, distance travelled upstream in 5 hours = 21*5 = 105 km.
The shaded region represents
y ? x
Let 45 x A = (25 x 900)/100
? A = (25 x 9)/45 = 5
CP = [100/(100 - Loss%) ] x SP
CP = 6000 x (100/75) = 8000
NA
Angle swept in 30 min= 180°
Area swept = [(22/7) x 7 x 7] x [180°/360°] cm2
= 77 cm2
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