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- Question
The present worth of a sum due sometime hence is Rs. 576 and the banker's gain is Rs. 16. The true discount is:
Options- A. 78
- B. 96
- C. 105
- D. 85
- Correct Answer
- 96
ExplanationT.D. = P.W. x B.G. = 576 x 16 = 96.
- 1. The bankers discount on Rs 1800 at 12 % per annum is equal to the true discount on Rs 1872 for the same time at the same rate .Find the time.
Options- A. 4 months
- B. 5 months
- C. 6 months
- D. 3 months Discuss
- 2. The banker's discount of a certain sum of money is Rs. 72 and the true discount on the same sum for the same time is Rs. 60. The sum due is:
Options- A. 290
- B. 480
- C. 360
- D. 420 Discuss
- 3. Two consecutive discounts x% and y% is equivalent to the discount
Options- A. (x-y+xy100)%
- B. (x+y+xy100)%
- C. (x-y-xy100)%
- D. (x+y-xy100)% Discuss
- 4. What is the difference between the banker's discount and the true discount on Rs.8100 for 3 months at 5%
Options- A. Rs. 2
- B. Rs. 1.25
- C. Rs. 2.25
- D. Rs. 0.5 Discuss
- 5. The banker's discount on a bill due 6 months hence at 6% is Rs. 18.54. What is the true discount?
Options- A. Rs. 24
- B. Rs. 12
- C. Rs. 36
- D. Rs. 18 Discuss
- 6. The present worth of a certain sum due sometime hence is Rs. 3400 and the true discount is Rs. 340. The banker's gain is:
Options- A. Rs. 21
- B. Rs. 17
- C. Rs. 18
- D. Rs. 34 Discuss
- 7. What is the present worth of a bill of Rs.1764 due 2 years hence at 5% compound interest is
Options- A. Rs. 1600
- B. Rs. 1200
- C. Rs. 1800
- D. Rs. 1400 Discuss
- 8. The B.D. and T.D. on a certain sum is Rs.200 and Rs.100 respectively. Find out the sum.
Options- A. Rs. 400
- B. Rs. 300
- C. Rs. 100
- D. Rs. 200 Discuss
- 9. A boat sails 15 km of a river towards upstream in 5 hours. How long will it take to cover the same distance downstream, if the speed of current is one-fourth the speed of the boat in still water:
Options- A. 1.8h
- B. 3h
- C. 4h
- D. 5h Discuss
- 10. A man can row 9 km/h in still water. It takes him twice as long as to row down. Find the rate of stream of the river?
Options- A. 3 1⁄3 Kmph
- B. 3 1⁄9Kmph
- C. 4 2⁄3 Kmph
- D. 4 1⁄3 Kmph Discuss
Banker's Discount problems
Search Results
Correct Answer: 4 months
Explanation:
S.I on Rs 1800 = T.D on Rs 1872
P.W of Rs 1872 is Rs 1800
Rs 72 is S.I on Rs 1800 at 12%
Time = (100 * 72)/(12 * 1800)
= 1/3 years = 4 months
Correct Answer: 360
Explanation:
Sum =(B.D. x T.D.)/(B.D. - T.D.)
= Rs. (72 x 60) / (72 - 60)
= Rs. (72 x 60) /12
= Rs. 360.
Correct Answer: (x+y-xy100)%
Correct Answer: Rs. 1.25
Explanation:
F = Rs. 8100
R = 5%
T = 3 months = 1/4 years
Therefore BD - TD = 101.25-100 = Rs.1.25
Correct Answer: Rs. 18
Explanation:
T= 6 months = 1/2 year
R = 6%
Correct Answer: Rs. 34
Explanation:
Correct Answer: Rs. 1600
Explanation:
Since the compound interest is taken here,
=> PW = 1600
Correct Answer: Rs. 200
Explanation:
Correct Answer: 3h
Explanation:
Upstream speed = B-S
Downstream speed = B+s
B-S = 15/5 = 3 km/h
Again B= 4S
Therefore B-S = 3= 3S
=> S = 1 and B= 4 km/h
Therefore B+S = 5km/h
Therefore, Time during downstream = 15/5 = 3h
Correct Answer: 4 2⁄3 Kmph
Explanation:
Let man’s rate upstream be x km/hr. Then his rate downstream is 3 x km/hr Given: Speed in still water = 9 (1/3) = 28/3 km/hr i.e, ½ (a+b) = 28/3 km/hr ½ (x+3x) = 28/3 2x = 28/3 x = 28/ 2 x 3 = 14/3 km/hr rate upstream b = 14/3 km/hr and rate downstream a = 14/3 x 3 = 14 km/hr speed of the current = ½ (a-b) = ½ (14 – 14/3) = ½ (42-14/3) = 28/6 = 4 (2/3) km/hr
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