Total sum of age of 80 students of the class = 15 X 80 = 1200 years
15 students ? 15 X 16 = 240 years
25 students ? 25 X 14 = 350 years
Sum of 40 students = 590 years
Total age of remaining 40 students = 1200 ? 590 = 610
So, average age = 15.25 years
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
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