3X + 4y = 240
by substitute through options 48 is correct
D _ C _ A --------(1)
D > B > C --------(2)
from (1) and (2)
D > B > C > A ---------(3)
Again E _ B _ A
But B > A, from (3)
So E > D > B > C > A [ Since B is the average of E and A so it is eqidistant from both E and A]
Amithab's total expenditure for Jan - June = 4200 x 6 = 25200
Expenditure for Feb - June = 25200-1200 = 24000
Expenditure for the months of Feb - July = 24000 + 1500 =25500
The average expenditure = 25500/6 = 4250
Let the number be 'x'.
= 11x
= 22x
=> x = 22.
One way to deal with fractions is to convert them all to decimals.
In this case all you would need to do is to see which is greater than 0.5.
Otherwise to see which is greater than ½, double the numerator and see if the result is greater than the denominator. In B doubling the numerator gives us 8, which is bigger than 7.
Required average = (67 * 2 + 35 * 2 + 6 * 3) / (2 + 2 + 3)
= (134 + 70 + 18) / 7 = 222 / 7 = 31(5/7) years.
Assuming Sripad has scored the least marks in subject other than science,
Then the marks he could secure in other two are 58 each.
Since the average mark of all the 3 subject is 65.
i.e (58+58+x)/3 = 65
116 + x = 195
x = 79 marks.
Therefore, the maximum marks he can score in maths is 79.
Total age of players in team = 22 x 11 = 242
When coach is included, total members = 12, Avg age increases by one becomes 23
Total age when coach is included = 23x12 = 276
Age of coach = 276-242 = 34 yrs.
Let average for 10 innings be x. Then,
(10x + 108)/11 = x + 6 => 11x + 66 = 10x + 108 => x = 42.
New average = (x + 6) = 48 runs.
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