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- Question
In a cinema hall for the matinee show which started at 2.30 pm and ended at 5.30 pm the vehicle parking lot had only three wheelers (auto rickshaws) and four wheelers. Today the wheels of the vehicles parked was counted and found to be 240. What could be the number of three wheelers parked therein ?
Options- A. 48
- B. 41
- C. 45
- D. 43
- Correct Answer
- 48
Explanation3X + 4y = 240
by substitute through options 48 is correct - 1. A man buys 3 cows and 18 goats in ? 47,200. Instead if he would have bought 8 cows and 3 goats, he had to pay ? 53,000 more. Cost of one cow is:
Options- A. ? 10,000
- B. ? 11,000
- C. ? 12,000
- D. ? 13,000 Discuss
- 2. Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?
Options- A. 16 years
- B. 18 years
- C. 20 years
- D. Cannot be determined
- E. None of these Discuss
- 3. (17.28 ÷? ) / (3.6 x 0.2) = 2
Options- A. 120
- B. 1.20
- C. 12
- D. 0.12 Discuss
- 4. If a, b and c are non-zero, a + (1/b) = 1 and b + (1/c) = 1, then the value of abc is
Options- A. -3
- B. 1
- C. -1
- D. 3 Discuss
- 5. A ladder 15 m long reaches a window which is 9 m above the ground on one side of street. Keeping its foot at the same point, the ladder is turned to the other side of the street to reach a window 12 m high. What is the width of the street:
Options- A. 31 m
- B. 12 m
- C. 30 m
- D. 21 m Discuss
- 6. 4, 2, 3.5, 7.5, 26.25, 118.125
Options- A. 118.125
- B. 26.25
- C. 3.5
- D. 2 Discuss
- 7. If the square of the sum of two numbers is equal to 4 times of their product. then the ratio of these numbers is:
Options- A. 2 : 1
- B. 1 : 3
- C. 1 : 1
- D. 1 : 2 Discuss
- 8. What is the area of a square having perimeter 68 cm?
Options- A. 361 sq cm
- B. 284 sq cm
- C. 269 sq cm
- D. 289 sq cm Discuss
- 9. A and B can do a job together in 7 days. A is 1¾ times as efficient as B. The same job can be done by A alone in :
Options- A.
9 1 days 3 - B. 11 days
- C.
12 1 days 4 - D.
16 1 days 3
Discuss
- 10. Area of a square is 1/2 hectare. The diagonal of the square is?
Options- A. 250 meter
- B. 100 meter
- C. 50? 2 meter
- D. 50 meter Discuss
More questions
Correct Answer: ? 12,000
Explanation:
Correct Answer: 16 years
Explanation:
| Then, | (6x + 6) + 4 | = | 11 |
| (5x + 6) + 4 | 10 |
⟹ 10(6x + 10) = 11(5x + 10)
⟹ 5x = 10
⟹ x = 2.
∴ Sagar's present age = (5x + 6) = 16 years.
Correct Answer: 12
Explanation:
Let (17.28 ÷ N ) / (3.6 x 0.2) = 2
Then, 17.28 / N = 1.44
? N = 17.28 / 1.44
= 12
Correct Answer: -1
Explanation:
? a + (1/b) = 1
ab + 1 = b ......(i)
Also, b + (1/c) = 1
? b = 1 - (1/c) ....(ii)
From Eqs. (i) and (ii), we get
ab + 1 = 1 - (1/c)
? ab = -1/c
? abc = -1
Correct Answer: 21 m
Explanation:
Draw a figure as per given question,
In a Right triangle ADC, Use the (Pythagoras Theorem)
AC = ?DC2 - AD2
? AC = ? 152 - 9 2
? AC = ? 225 - 81
? AC = ? 144
? AC = 12 cm
In a Right triangle BCE, Use the formula
CB = ? CD2 - BE2
? CB = ?15 2 - 122
? CB = ?225 - 144
? CB = ? 81
? CB = 9 m
? Width of the street (AC + BC) = AB = 12 + 9 = 21 m.
Correct Answer: 3.5
Explanation:
Series pattern 4 x 0.5 = 2
2 x 1.5 = 3
Should come in place of 3.5
3 x 2.5 = 7.5
7.5 x 3.5 = 26.25
26.25 x 4.5 = 118.125
Clearly, 3.5 is wrong and is replaced by 3.
Correct Answer: 1 : 1
Explanation:
Let the number be p and q.
According to question,
(p + q)2 = 4pq
? p2 + q2 + 2pq ? 4pq = 0
? (p ? q)2 = 0
? p = q
Hence , required ratio is 1 : 1 .
Correct Answer: 269 sq cm
Explanation:
According to the question,
4a = 68 [ where a = side]
?a = 68/4 = 17 cm
? Required area = a2
= (17)2 = 289 sq cm
Correct Answer: 11 days
Explanation:
| (A's 1 day's work) : (B's 1 day's work) = | 7 | : 1 = 7 : 4. |
| 4 |
Let A's and B's 1 day's work be 7x and 4x respectively.
| Then, 7x + 4x = | 1 | ⟹ 11x = | 1 | ⟹ x = | 1 | . |
| 7 | 7 | 77 |
| ∴ A's 1 day's work = | ❨ | 1 | x 7 | ❩ | = | 1 | . |
| 77 | 11 |
Correct Answer: 100 meter
Explanation:
Area = 1/2 hectare = 10000 / 2 m2
= 5000 m2
Again Area = 1/2 x (Diagonal)2
So 1/2 x (Diagonal)2 = 5000m2
? Diagonal2= 10000
? Diagonal = 100
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