You could solve this by drawing a Venn diagram. A simpler way is to realize that you can subtract the number of students taking both languages from the numbers taking French to find the number taking only French. Likewise find those taking only German. Then we have:Total = only French + only German + both + neither
78 = (41-9) + (22-9) + 9 + neither.
Not enrolled students = 24
Let the number of boys = x
From the given data,
=> [21x + 16(18)]/(x+16) = 19
=> 21x - 19x = 19(16) - 16(18)
=> 2x = 16
=> x = 8
Therefore, the number of boys in the class = 8.
Let x, x+2, x+4, x+6, x+8 and x+10 are six consecutive odd numbers.
Given that their average is 52
Then, x + x+2 + x+4 + x+6 + x+8 + x+10 = 52×6
6x + 30 = 312
x = 47
So Product = 47 × 57 = 2679
Age of the teacher = (37 * 15 - 36 * 14) years = 51 years.
We Know that sum of the n natural numbers =
Then sum of 50 natural numbers= = 1250
Average of the 50 natural numbers = = 25.5
Average = (76 + 65 + 82 + 67 + 85 )/ 5 = 375/5 = 75.
Let their prices be 3x, 5x and 7x.
Then, 3x + 5x + 7x = (15000 * 3) or x = 3000.
Cost of cheapest item = 3x = Rs. 9000.
Let the expenditure on the 95 students be 'x'
Then,
95x + 500 = 120(x ? 5)
95x + 500 = 120x - 600
120x - 95x = 1100
25x = 1100
=> x = 44
Therefore, total expenditure of the hostel becomes
95 x 44 + 500 = 4680.
Let Arun's weight be X kg.
According to Arun, 65 < X < 72.
According to Arun's brother, 60 < X < 70.
According to Arun's mother, X < 68.
The values satisfying all the above conditions are 66 and 67.
Required average = (66 + 67) / 2 = 66.5 kg
Given,
mean of 100 observations is 40
=> Total of 100 observations = 40 x 100 = 4000
84 is misread as 48
=> Difference = 84 - 48 = 36
=> Now, new total of 100 observations = 4000 + 36 = 4036
Correct Mean = 4036/100 = 40.36
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