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- Question
A grocer has a sale of Rs 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6500 ?
Options- A. 4991
- B. 5467
- C. 5987
- D. 6453
- Correct Answer
- 4991
ExplanationTotal sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6500 x 6) - 34009]
= Rs. (39000 - 34009)
= Rs. 4991.
- 1. The average of runs of a cricket player of 10 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4 ?
Options- A. 76
- B. 79
- C. 85
- D. 87 Discuss
- 2. Length and breadth of a rectangle are 8 cm and 6 cm respectively. The rectangle is cut on its four vertices such that the resulting figure is a regular octagon. What is the side (in cm) of the octagon?
Options- A. 3(?11) ? 7
- B. 5(?13) ? 8
- C. 4(?7) ? 11
- D. 6(?11) ? 9 Discuss
- 3. ABC is a triangle. AB = 5 cm, AC = ?41 cm and BC = 8 cm. AD is perpendicular to BC. What is the area (in cm2) of triangle ABD?
Options- A. 12
- B. 6
- C. 10
- D. 20 Discuss
- 4. The radius of two circles is 3 cm and 4 cm. The distance between the centres of the circles is 10 cm. What is the ratio of the length of direct common tangent to the length of the transverse common tangent?
Options- A. ?51 : ?68
- B. ?33 : ?17
- C. ?66 : ?51
- D. ?28 : ?17 Discuss
- 5. AB and AC are the two tangents to a circle whose radius is 6 cm. If ?BAC = 60 deg, then what is the value (in cm) of ?(AB2 + AC2) ?
Options- A. 6?6
- B. 4?6
- C. 9?3
- D. 8?3 Discuss
- 6. The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero ?
Options- A. 0
- B. -1
- C. 1
- D. none of these Discuss
- 7. The average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ?
Options- A. 70 kg
- B. 75 kg
- C. 80 kg
- D. 85 kg Discuss
- 8. The average of five consecutive odd numbers is 61. What is the difference between the highest and lowest numbers :
Options- A. 4
- B. 8
- C. 12
- D. 16 Discuss
- 9. The average weight of a class of 24 students is 35 kg. If the weight of the teacher be included, the average rises by 400 g. The weight of the teacher is :
Options- A. 45 kg
- B. 46 kg
- C. 47 kg
- D. 48 kg Discuss
- 10. The average of 7 consecutive numbers is 20. The largest of these numbers is :
Options- A. 21
- B. 22
- C. 23
- D. 24 Discuss
Average problems
Search Results
Correct Answer: 76
Explanation:
Average = total runs / no.of innings = 32
So, total = Average x no.of innings = 32 x 10 = 320.
Now increase in avg = 4runs. So, new avg = 32+4 = 36runs
Total runs = new avg x new no. of innings = 36 x 11 = 396
Runs made in the 11th inning = 396 - 320 = 76
Correct Answer: 3(?11) ? 7
Correct Answer: 6
Correct Answer: ?33 : ?17
Correct Answer: 6?6
Correct Answer: 0
Explanation:
Average of 20 numbers = 0.
Sum of 20 numbers = (0 * 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (- a).
Correct Answer: 85 kg
Explanation:
Total weight increased = (8 x 2.5) kg = 20 kg.
Weight of new person = (65 + 20) kg = 85 kg.
Correct Answer: 8
Explanation:
Let the numbers be x, x + 2, x + 4, x + 6 and x + 8.
Then [x + (x + 2) + (x + 4) + (x + 6) + (x + 8) ] / 5 = 61.
or 5x + 20 = 305 or x = 57.
So, required difference = (57 + 8) - 57 = 8
Correct Answer: 45 kg
Explanation:
Weight of the teacher = (35.4 x 25 - 35 x 24) kg = 45 kg.
Correct Answer: 23
Explanation:
Let the numbers be x, x + 1, x + 2, x + 3, x + 4, x + 5 and x + 6,
Then (x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6)) / 7 = 20.
or 7x + 21 = 140 or 7x = 119 or x =17.
Latest number = x + 6 = 23.
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