P=4s
We know that,
Perimeter of rectangle = 2(L+W) = 2(5 + 2) = 2 (7) = 14 fts.
A=lb
let original radius = r and new radius = (50/100) r = r/2
original area =
and new area =
decrease in area =
*
*100 = 75%
Let the inner and outer radii be r and R metres.
Then
=> Width of the ring = (R - r) = (12 - 8) m = 4 m.
Area to be plastered= [2(l + b) x h] + (l x b)
= [2(25 + 12) x 6] + (25 x 12)
= (444 + 300)
= 744 sq.m
Cost of plastering = Rs.744 x (75/100)
P = 2l + 2w
Ratio of length and breadth is 6 : 5
? Length = 6x
Breadth = 5x
? Area = l x b = 30x2
? Perimeter = 2 (l + b) = 2(6x + 5x) =22x
? (30*x*x)/(22x)= 60/11
? X = 4
? Length = 6x = 6 x 4 = 24 units
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