Discussion
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- Question
The diameter of a circle is 28 cm find its area?
Options- A. 616 sq cm
- B. 308 sq cm
- C. 154 sq cm
- D. 77 sq cm
- Correct Answer
- 616 sq cm
- 1. The area of a circular cricket ground is 24.64 hectares. Find the cost of making rope boundary at the rate of Rs. 5.40 per metre.
Options- A. Rs. 9,600
- B. Rs. 9,504
- C. Rs. 9,802
- D. Rs. 9,876 Discuss
- 2. All sides are congruent in a _____.
Options- A. Rectangle
- B. Parallelogram
- C. Rhombus
- D. Kite Discuss
- 3. ABCDEF is a regular hexagon of side 12 cm. What is the area (in cm2) of the triangle ECD?
Options- A. 18?3
- B. 24?3
- C. 36?3
- D. 42?3 Discuss
- 4. ?ABC is an isosceles right angled triangle having ?C = 90°. If D is any point on AB, then AD2+ BD2 is equal to
Options- A. CD2
- B. 2CD2
- C. 3CD2
- D. 4CD2 Discuss
- 5. An equilateral triangle of side 6 cm is inscribed in a circle. Then radius of the circle is
Options- A. 2?3 cm
- B. 3?2 cm
- C. 4?3 cm
- D. ?3 cm Discuss
- 6. The measures of the four angles of a quadilateral are in the ratio 3:4:5:6. What is the measure of the biggest angle?
Options- A. 120°
- B. 100°
- C. 80°
- D. 60° Discuss
- 7. A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:
Options- A. rs.458
- B. rs,558
- C. rs.658
- D. rs.758 Discuss
- 8. Two concentric circles form a ring. The inner and outer circumferences of ring are 5187 m and 3527 m respectively. Find the width of the ring.
Options- A. 4
- B. 5
- C. 6
- D. 7 Discuss
- 9. If the radius of a circle is decreased by 50% , find the percentage decrease in its area.
Options- A. 75%
- B. 65%
- C. 35%
- D. 25% Discuss
- 10. The length of a rectangle is 12 cm. What is the width if the area is 72 cm ?
Options- A. 6cm
- B. 5cm
- C. 3cm
- D. 4cm Discuss
Area problems
Search Results
Correct Answer: Rs. 9,504
Correct Answer: Rhombus
Correct Answer: 36?3
Correct Answer: 2CD2
Correct Answer: 2?3 cm
Correct Answer: 120°
Correct Answer: rs,558
Explanation:
Area to be plastered= [2(l + b) x h] + (l x b)
= [2(25 + 12) x 6] + (25 x 12)
= (444 + 300)
= 744 sq.m
Cost of plastering = Rs.744 x (75/100)
Correct Answer: 4
Explanation:
Let the inner and outer radii be r and R metres.
Then
=> Width of the ring = (R - r) = (12 - 8) m = 4 m.
Correct Answer: 75%
Explanation:
let original radius = r and new radius = (50/100) r = r/2
original area =
and new area =
decrease in area =
*
*100 = 75%
Correct Answer: 6cm
Explanation:
A=lb
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