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- Question
The diagonals of two squares are in the ratio of 2:5. Find the ratio of their areas.
Options- A. 2:25
- B. 3:25
- C. 4:25
- D. 6:25
- Correct Answer
- 4:25
Explanationlet the diagonals of the squares be 2x and 5x respectively
ratio of their areas = = 4:25
- 1. A sector of 120, cut out from a circle, has an area of 667cm2 . Find the radius of the circle ?
Options- A. 1
- B. 2
- C. 3
- D. 4 Discuss
- 2. The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
Options- A. 40
- B. 20
- C. 30
- D. none of these Discuss
- 3. Two circles touch each other at point X. A common tangent touch them at two distinct points Y and Z. If another tangent passing through X cut YZ at A and XA= 16 cm, then what is the value (in cm) of YZ?
Options- A. 18
- B. 24
- C. 16
- D. 32 Discuss
- 4. Three medians AD, BE and CF of ?ABC intersect at G; Area of ?ABC is 36 sq cm. Then the area of ?CGE is
Options- A. 12 sq cm
- B. 6 sq cm
- C. 9 sq cm
- D. 18 sq cm Discuss
- 5. The area of a triangle with vertices A (0, 8) , O (0,0) and B (5, 0) is:
Options- A. 8 sq. units
- B. 13 sq. units
- C. 20 sq. units
- D. 40 sq. units Discuss
- 6. If the area of a square with side a s equal to the area of a triangle with base a, then the altitude of the triangle is
Options- A. a
- B. 2a
- C. 5a
- D. 3a Discuss
- 7. Find the perimeter and area of a square that has a side of length 14 feet.
Options- A. 176
- B. 186
- C. 196
- D. 206 Discuss
- 8. If a parallelogram with area p, a triangle with area R and a triangle with area T are all constructed on the same base and all have the same altitude, then
Options- A. P=R
- B. P=A
- C. P=A/2
- D. P=2R Discuss
- 9. A man walked diagonally across a square plot. Approximately what was the percent saved by not walking along the edges?
Options- A. 10%
- B. 20%
- C. 30%
- D. 40% Discuss
- 10. The area of a rectangle is 80 cm.If its length is 16 cm, what is its width?
Options- A. 5cm
- B. 10cm
- C. 15cm
- D. 20cm Discuss
Area problems
Search Results
Correct Answer: 3
Explanation:
Let the radius of the circle be r cm. Then,
r=3.
Correct Answer: none of these
Explanation:
Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter =5300/23.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.
Correct Answer: 32
Correct Answer: 6 sq cm
Correct Answer: 20 sq. units
Correct Answer: 2a
Explanation:
Area of a square with side a = a² sq unts
Area of a triangle with base a = (1/2) * a * h sq.unts
a² =1/2 *a *h
=> h = 2a
altitude of the triangle is 2a
Correct Answer: 196
Explanation:
Perimeter of a square p=4s ,where s=length of its side
=> p=4(14)=56 feets
Area of a square A = s x s
=> A=196
The perimeter is 56 feet, and the area is 196 square feet.
Correct Answer: P=R
Explanation:
let each have base = b and height = h
then p = b*h, R = b*h and T = (1/2) * b*h
so P = R, P = 2T and T = (1/2)*R are all correct statements
Correct Answer: 30%
Explanation:
let the side of the square be x meters
length of two sides = 2x meters
diagonal =
= 1.414x m
saving on 2x meters = .59x m
saving % = %
= 30% (approx)
Correct Answer: 5cm
Explanation:
A=LB
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