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- Question
A cow s tethered in the middle of a field with a 14feet long rope.If the cow grazes 100 sq feet per day, then approximately what time will be taken by the cow to graze the whole field?
Options- A. 616
- B. 716
- C. 816
- D. 516
- Correct Answer
- 616
Explanationarea of the field grazed = (22/7) * 14 * 14 = 616 sq feet
- 1. The perimeters of two squares are 40cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.
Options- A. 12
- B. 24
- C. 36
- D. 48 Discuss
- 2. Two concentric circles form a ring. The inner and outer circumference of the ring are 352/7 m and 528/7m respectively.Find the width of the ring.
Options- A. 5
- B. 4
- C. 3
- D. 2 Discuss
- 3. Chord AB of a circle when extended meets the tangent to the circle at point P. PT is the tangent touching the circle at point T. If lengths of PT and PB are 6 cm and 4 cm respectively, what is the length of PA?
Options- A. 12 cm
- B. 11 cm
- C. 10 cm
- D. 9 cm Discuss
- 4. Calculate the number of bricks, each measuring 25 cm x 15 cm x 8 cm required to construct a wall of dimensions 10 m x 4 cm x 6 m when 10% of its volume is occupied by mortar ?
Options- A. 720
- B. 600
- C. 660
- D. 6000 Discuss
- 5. A class is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the class room ?
Options- A. 115
- B. 117
- C. 116
- D. 114 Discuss
- 6. Wheels of diameters 7cm and 14cm start rolling simultaneously from x & y which are 1980 cm apart towards each other in opposite directions. Both of them make the same number of revolutions per second. If both of them meet after 10seconds.The speed of the smaller wheel is
Options- A. 22m/s
- B. 33m/s
- C. 44m/s
- D. 55m/s Discuss
- 7. The length of the rectangle is 20% more than its breadth . what will be the ratio of the area of the rectangle to that of the square whose side is equal to the breadth of the rectangle?
Options- A. 2:1
- B. 5:6
- C. 6:5
- D. data is inadequate Discuss
- 8. The perimeter of a square is equal to twice the perimeter of a rectangle of length 8cm and breadth 7cm. What is the circumference of a semicircle whose diameter is equal to the side of the square ?
Options- A. 55.12 cm
- B. 22.54 cm
- C. 42.51 cm
- D. 38.57 cm Discuss
- 9. If a 36 cm thread is used to wrap a book, lengthwise twice and breadth wise once, what is the size of the book ?
Options- A. 288 sq.cm
- B. 188 sq.cm
- C. 144 sq.cm
- D. 244 sq.cm Discuss
- 10. Let A(O,-1), B(0,3) and C(2,1) be three points. Let ?1 be the area of the triangle ABC and ?2 be the area of the triangle formed by the mid points of the sides of the triangle whose vertices are A, B and C such that ?1 =1 , ?2=x Find the value of x .
Options- A. 4
- B. 5
- C. 2
- D. 3 Discuss
Area problems
Search Results
Correct Answer: 24
Explanation:
side of first square = 40/4 =10cm
side of second square = 32/4 = 8cm
area of third squre = 10² - 8² = 36 sq cm
side of third square = = 6 cm
required perimeter = 6*4 = 24cm
Correct Answer: 4
Explanation:
let the inner and outer radii be r and R meters
then,
= 352/7
=> r = (352/7) * (7/22) * (1/2) = 8m
= 528/7
=> R= (528/7) * (7/22) * (1/2)= 12m
width of the ring = R-r = 12-8 = 4m
Correct Answer: 9 cm
Correct Answer: 720
Explanation:
Let the number of bricks be 'N'
10 x 4/100 x 6 x 90/100 = 25/100 x 15/100 x 8/100 x N
10 x 4 x 6 x 90 = 15 x 2 x N => N = 720.
Correct Answer: 117
Explanation:
Length = 6 m 24 cm = 624 cm
Width = 4 m 32 cm = 432 cm
HCF of 624 and 432 = 48
Number of square tiles required = (624 x 432)/(48 x 48) = 13 x 9 = 117.
Correct Answer: 22m/s
Explanation:
let each wheel make x revolutions per sec. Then
distance moved by smaller wheel in 3 revolutions
=
speed of smaller wheel = m/s = 22m/s
Correct Answer: 6:5
Explanation:
Required ratio =
Correct Answer: 38.57 cm
Explanation:
We know that perimeter of rectangle = 2(l+b) = 2(8+7)= 30cm
Given perimeter of square is twice the perimeter of rectangle = 2(30) = 60cm
Therefore, side of the square is = 1/4 x 60 = 15cm
Circumference of the required semicircle =
=
= 23.57 + 15 = 38.57cm.
Correct Answer: 288 sq.cm
Explanation:
Length of the thread is 36 cms.
length wise twice breath wise once then totally thrice.
so 36/3 = 12.
so length is 12 x 2 = 24 cms
breath is 12 cms
Area of the book = length x breath = 24 x 12 = 288 sq.cm
Correct Answer: 3
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