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- Question
2 metres broad pathway is to be constructed around a rectangular plot on the inside. The area of the plots is 96 sq.m. The rate of construction is Rs. 50 per square metre. Find the total cost of the construction?
Options- A. 20
- B. 30
- C. 40
- D. data is inadequate
- Correct Answer
- data is inadequate
ExplanationGiven lb =96
Area of pathway = [(l-4)(b-4)-lb] = 16-4(l+b)
Which cannot be determined. so, data is inadequate.
- 1. A triangle has a perimeter 13. The two shorter sides have integer lengths equal to x and x + 1. Which of the following could be the length of the other side?
Options- A. 4
- B. 6
- C. 8
- D. None of the above Discuss
- Option A cannot be correct because 4 would not be the longest side.(sides 4, 5, and 4)
- Option B could be correct because the other two sides would be 3 and 4.
- Option C cannot be correct because this third side would be greater than the sum of the other two sides.
- 2. A 3 by 4 rectangle is inscribed in circle. What is the circumference of the circle?
Options- A. 2.5?
- B. 3?
- C. 5?
- D. 4? Discuss
- 3. The perimeter of a rectangle is 160 cm. The rectangle is 4 times longer than wide. What are the length and width of this rectangle?
Options- A. l=65;b=16
- B. l=16;b=64
- C. l=64;b=16
- D. l=16;b=48 Discuss
- 4. The perimeter of a square is 40 meters. Find the length of one side of the square
Options- A. 10m
- B. 20m
- C. 30m
- D. 40m Discuss
- 5. A rectangular paper when folded into two congruent parts had a perimeter of 34cm foer each part folded along one set of sides and the same is 38cm. When folded along the other set of sides. What is the area of the paper?
Options- A. 140
- B. 150
- C. 160
- D. 170 Discuss
- 6. The edge of three cubes of metal is 3 m, 4 m and 5 m. They are melted and formed into a single cube. Find the edge of the new cube ?
Options- A. 15 m
- B. 4 m
- C. 6 m
- D. 9 m Discuss
- 7. A class is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the class room ?
Options- A. 115
- B. 117
- C. 116
- D. 114 Discuss
- 8. Calculate the number of bricks, each measuring 25 cm x 15 cm x 8 cm required to construct a wall of dimensions 10 m x 4 cm x 6 m when 10% of its volume is occupied by mortar ?
Options- A. 720
- B. 600
- C. 660
- D. 6000 Discuss
- 9. Chord AB of a circle when extended meets the tangent to the circle at point P. PT is the tangent touching the circle at point T. If lengths of PT and PB are 6 cm and 4 cm respectively, what is the length of PA?
Options- A. 12 cm
- B. 11 cm
- C. 10 cm
- D. 9 cm Discuss
- 10. Two concentric circles form a ring. The inner and outer circumference of the ring are 352/7 m and 528/7m respectively.Find the width of the ring.
Options- A. 5
- B. 4
- C. 3
- D. 2 Discuss
Area problems
Search Results
Correct Answer: 6
Explanation:
The measure of the third side of a triangle must lie between the sum and the difference of the other two sides. Using this fact along with the answer choices, we can eliminate the wrong answers.
Correct Answer: 5?
Explanation:
Draw the diagram. The diagonal of the rectangle is the diameter of the circle. The diagonal is the hypotenuse of a 3,4,5 triangle and is therefore, 5.
Circumference = ?.diameter = 5?
Correct Answer: l=64;b=16
Explanation:
P=2(l+b)
l=4b
Correct Answer: 10m
Explanation:
P = 4 x s
Correct Answer: 140
Explanation:
when folded along the breadth
we have 2(l/2 +b) = 34 or l+2b = 34...........(1)
when folded along the length, we have 2(l+b/2)=38 or 2l+b =38.....(2)
from 1 &2 we get l=14 and b=10
Area of the paper = 14*10 = 140 sq cm
Correct Answer: 6 m
Explanation:
The edge of the new cube is = => a = 6 m.
Correct Answer: 117
Explanation:
Length = 6 m 24 cm = 624 cm
Width = 4 m 32 cm = 432 cm
HCF of 624 and 432 = 48
Number of square tiles required = (624 x 432)/(48 x 48) = 13 x 9 = 117.
Correct Answer: 720
Explanation:
Let the number of bricks be 'N'
10 x 4/100 x 6 x 90/100 = 25/100 x 15/100 x 8/100 x N
10 x 4 x 6 x 90 = 15 x 2 x N => N = 720.
Correct Answer: 9 cm
Correct Answer: 4
Explanation:
let the inner and outer radii be r and R meters
then,
= 352/7
=> r = (352/7) * (7/22) * (1/2) = 8m
= 528/7
=> R= (528/7) * (7/22) * (1/2)= 12m
width of the ring = R-r = 12-8 = 4m
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