Discussion
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- Question
If the perimeters of a square and a rectangle are the same, then the area a & b enclosed by them would satisfy the condition:
Options- A. a
- B. a>b
- C. a=b
- D. none
- Correct Answer
- a>b
ExplanationTake a square of side 4cm and a rectangle having l=6cm and b=2cm
then perimeter of square = perimeter of rectangle
area of square = 16 sq.cm
area of rectangle = 12 sq.cm
Hence a >b
- 1. If each side of a square is increased by 25%, find the percentage change in its area.
Options- A. 56.25%
- B. 36.25%
- C. 16.25%
- D. 12.25% Discuss
- 2. The ratio of bases of two triangles is x:y and that of their areas is a:b. Then the ratio of their corresponding altitudes wll be
Options- A. ay:bx
- B. a:b
- C. x:y
- D. bx:ay Discuss
- 3. A rectangular grassy plot 110m by 65cm has a gravel path .5cm wide all round it on the inside. Find the cost of gravelling the path at 80 paise per sq.mt
Options- A. 680rs
- B. 480rs
- C. 340rs
- D. 320rs Discuss
- 4. In a rectangle, length is three times its breadth. If the length and the breadth of the rectangle are increased by 30% and 100% respectively, then its perimeter increases by
Options- A. 40/3%
- B. 20%
- C. 25%
- D. 27% Discuss
- 5. An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq. m ?
Options- A. Rs. 4082.40
- B. Rs. 1024.21
- C. Rs. 2810.6
- D. Rs. 3214 Discuss
- 6. The area of a square field is 69696sq.cm..its diagonal will be equal to
Options- A. 373
- B. 573
- C. 473
- D. 673 Discuss
- 7. What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad ?
Options- A. 844
- B. 814
- C. 840
- D. 820 Discuss
- 8. A parallelogram PQRS, the length of whose sides are 8 cm and 12 cm, has one diagonal 10 cm long Ile length of the other diagonal is approximately:
Options- A. 17.8 cm
- B. 17.5 cm
- C. 17 cm
- D. 18 cm Discuss
- 9. The area of a field in the shape of a trapezium measures 1440sq m. The perpendicular distance between its parallel sides is 24cm. If the ratio of the sides is 5:3, the length of the longer parallel side is:
Options- A. 75
- B. 85
- C. 95
- D. 105 Discuss
- 10. A rectangular paper when folded into two congruent parts had a perimeter of 34cm foer each part folded along one set of sides and the same is 38cm. When folded along the other set of sides. What is the area of the paper?
Options- A. 140
- B. 150
- C. 160
- D. 170 Discuss
Area problems
Search Results
Correct Answer: 56.25%
Explanation:
Let each side of the square be a. Then, area = .
New side =
. New area =
=
Increase in area =
Increase% =
% = 56.25%.
Correct Answer: ay:bx
Explanation:
a : b =(1/2 * x * H) : (1/2 * y * h)
bxH = ayh => H/h =ay/bx
Hence H:h = ay:bx
Correct Answer: 680rs
Explanation:
area of theplot = 110 * 65 = 7150 sq.m
area of the plot excluding the path = (110-5)* (65-5) = 6300 sq.m
area of the path = 7150 - 6300 =850 sq.m
cost of gravelling the path = 850 x (80/100) = 680 Rs
Correct Answer: 25%
Explanation:
Correct Answer: Rs. 4082.40
Explanation:
Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 x 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40
Correct Answer: 373
Explanation:
Correct Answer: 814
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) sq.cm
Required number of tiles =1517 x 902/(41 x 41) = 814.
Correct Answer: 17.8 cm
Correct Answer: 75
Explanation:
Area of field = = 96x sq.m
96x = 1440 => x = = 15
Hence, the length of longer parallel side = 5x = 75m
Correct Answer: 140
Explanation:
when folded along the breadth
we have 2(l/2 +b) = 34 or l+2b = 34...........(1)
when folded along the length, we have 2(l+b/2)=38 or 2l+b =38.....(2)
from 1 &2 we get l=14 and b=10
Area of the paper = 14*10 = 140 sq cm
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