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- Question
A rectangular parking space is marked out by painting three of its sides.If the length of the unpainted side is 9 feet, and the sum of the lengths of the painted sides is 37 feet, then what is the area of the parking space in square feet?
Options- A. 126sq.ft
- B. 120sq.ft
- C. 130sq.ft
- D. 135sq.ft
- Correct Answer
- 126sq.ft
ExplanationLet l = 9 ft.
Then l + 2b = 37
=> 2b = 37 ? l = 37 ? 9 = 28
b = 28/2 = 14 ft.
Area = lb = 9 × 14 = 126 sq. ft.
- 1. If a square and a rhombus stand on the same base, then the ratio of the areas of the square and the rhombus is:
Options- A. 1:1
- B. 1:2
- C. 1:3
- D. 1:4 Discuss
- 2. If length of each side of a rhombus PQRS is 8 cm and ?PQR = 120°, then what is the length (in cm) of QS?
Options- A. 4?5
- B. 6
- C. 8
- D. 12 Discuss
- 3. A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?
Options- A. 315
- B. 385
- C. 415
- D. 485 Discuss
- 4. A rectangular plot measuring 90 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?
Options- A. 65m
- B. 45m
- C. 55m
- D. 56m Discuss
- 5. Four circular cardboard pieces, each of radius 7cm are placed in such a way that each piece touches two other pieces. The area of the space encosed by the four pieces is
Options- A. 12
- B. 32
- C. 42
- D. 52 Discuss
- 6. The length of a rope in meter by which a cow must be tethered in order that she may be able to graze an area of 2826 sq.m is ?
Options- A. 15 mts
- B. 30 mts
- C. 24 mts
- D. 36 mts Discuss
- 7. An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq. m ?
Options- A. Rs. 4082.40
- B. Rs. 1024.21
- C. Rs. 2810.6
- D. Rs. 3214 Discuss
- 8. In a rectangle, length is three times its breadth. If the length and the breadth of the rectangle are increased by 30% and 100% respectively, then its perimeter increases by
Options- A. 40/3%
- B. 20%
- C. 25%
- D. 27% Discuss
- 9. A rectangular grassy plot 110m by 65cm has a gravel path .5cm wide all round it on the inside. Find the cost of gravelling the path at 80 paise per sq.mt
Options- A. 680rs
- B. 480rs
- C. 340rs
- D. 320rs Discuss
- 10. The ratio of bases of two triangles is x:y and that of their areas is a:b. Then the ratio of their corresponding altitudes wll be
Options- A. ay:bx
- B. a:b
- C. x:y
- D. bx:ay Discuss
Area problems
Search Results
Correct Answer: 1:1
Explanation:
A square and a rhombus on the same base are equal in area
Correct Answer: 8
Correct Answer: 315
Explanation:
Let the areas of the two parts be x and (700-x) hectares
therefore,
So, the two parts are 385 and 315.
Hence, Area of the smaller = 315 hectares
Correct Answer: 56m
Explanation:
perimeter of the plot = 2(90+50) = 280m
no of poles =280/5 =56m
Correct Answer: 42
Explanation:
required area = [14 x 14 - (4 x 1/4 x 22/7 x 7 x 7) ]sq.cm
= 196 - 154 = 42 sq.cm.
Correct Answer: 30 mts
Explanation:
The cow can graze an area of 2826 sq.m i.e it is able to cover area of circle of 2826 sq.m
Therefore,
=2826
=(2826×7/22) = 899.18 = 900
r = 30 m.
Therefore, the radius of the circle implies the length of the rope = 30 mts.
Correct Answer: Rs. 4082.40
Explanation:
Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 x 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40
Correct Answer: 25%
Explanation:
Correct Answer: 680rs
Explanation:
area of theplot = 110 * 65 = 7150 sq.m
area of the plot excluding the path = (110-5)* (65-5) = 6300 sq.m
area of the path = 7150 - 6300 =850 sq.m
cost of gravelling the path = 850 x (80/100) = 680 Rs
Correct Answer: ay:bx
Explanation:
a : b =(1/2 * x * H) : (1/2 * y * h)
bxH = ayh => H/h =ay/bx
Hence H:h = ay:bx
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