perimeter of the plot = 2(90+50) = 280m
no of poles =280/5 =56m
Let the length of each train = L metres
Relative speed = (46 - 36) = 10 km/hr. = 10 x (5/18) = 25/9 m/sec
Distance covered in crossing = (L + L) = 2L metres
? 2L x (9/25) = 36
? L = (25 x 36)/(2 x 9) = 50 metres.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.