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- Question
A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed?
Options- A. 56m
- B. 65m
- C. 34m
- D. 36m
- Correct Answer
- 56m
ExplanationLength of the wire fencing = perimeter = 2(90 + 50) = 280 metres
Two poles will be kept 5 metres apart. Also remember that the poles will be placed along the perimeter of the rectangular plot, not in a single straight line which is very important.
Hence number of poles required = 280 / 5 = 56
- 1. What is the least number of squares tiles required to pave the floor of a room 15.17 m long and 9.02 m broad?
Options- A. 814
- B. 714
- C. 614
- D. 713 Discuss
- 2. The perimeter of a rectangle whose length is 6 m more than its breadth is 84 m. What will be the area of the rectangle?
Options- A. 333 sq.mts
- B. 330 sq.mts
- C. 362 sq.mts
- D. 432 sq.mts Discuss
- 3. Find the ratio of the areas of the incircle and circumcircle of a square ?
Options- A. 1 : 4
- B. 4 : 1
- C. 2 : 1
- D. 1 : 2 Discuss
- 4. A room is 15 feet long and 12 feet broad. A mat has to be placed on the floor of the room leaving 1.5 feet space from the walls. What will be the cost of the mat at the rate of Rs. 3.50 per squire feet?
Options- A. 378
- B. 472.5
- C. 496
- D. 630 Discuss
- 5. The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
Options- A. 20
- B. 200
- C. 300
- D. 400 Discuss
- 6. The length and the breadth of rectangular field are in the ratio of 8 : 7. If charges of the painting the boundary of rectangle is at Rs. 10 per meter is Rs. 3000. What is the area of rectangular plot?
Options- A. 5600 sq.m
- B. 1400 sq. m
- C. 4400 sq.m
- D. 3600 sq.m Discuss
- 7. If the length of a certain rectangle is decreased by 4 cm and the width is increased by 3 cm, a square with the same area as the original rectangle would result. Find the perimeter of the original rectangle.
Options- A. 20
- B. 30
- C. 40
- D. 50 Discuss
- 8. The no of revolutions a wheel of diameter 40cm makes in traveling a distance of 176m is
Options- A. 240
- B. 140
- C. 40
- D. 340 Discuss
- 9. A wheel makes 1000 revolutions in covering a distance of 88 km. Find the radius of the wheel.
Options- A. 14
- B. 13
- C. 12
- D. 11 Discuss
- 10. A circular swimming pool is surrounded by a concrete wall 4ft wide. If the area of the concrete wall surrounding the pool is 11/25 that of the pool, then the radius of the pool is?
Options- A. 10ft
- B. 20ft
- C. 30ft
- D. 40ft Discuss
Area problems
Search Results
Correct Answer: 814
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile =
Required number of tiles = = 814
Correct Answer: 432 sq.mts
Explanation:
Let the breadth of the rectangle = b mts
Then Length of the rectangle = b + 6 mts
Given perimeter = 84 mts
2(L + B) = 84 mts
2(b+6 + b) = 84
2(2b + 6) = 84
4b + 12 = 84
4b = 84 - 12
4b = 72
b = 18 mts
=> Length = b + 6 = 18 + 6 = 24 mts
Now, required Area of the rectangle = L x B = 24 x 18 = 432 sq. mts
Correct Answer: 1 : 2
Correct Answer: 378
Correct Answer: 200
Explanation:
Let length of plot = L meters, then breadth = L - 20 meters
and perimeter = 2[L + L - 20] = [4L - 40] meters
[4L - 40] * 26.50 = 5300
[4L - 40] = 5300 / 26.50 = 200
4L = 240
L = 240/4= 60 meters.
Correct Answer: 5600 sq.m
Explanation:
Perimeter of the rectangle is given by 3000/10 = 300 mts
But we know,
The Perimeter of the rectangle = 2(l + b)
Now,
2(8x + 7x) = 300
30x = 300
x = 10
Required, Area of rectangle = 8x x 7x = 56 x 100 = 5600 sq. mts.
Correct Answer: 50
Explanation:
Let x and y be the length and breadth of the rectangle respectively.
Then, x - 4 = y + 3 or x - y = 7 ----(i)
Area of the rectangle =xy; Area of the square = (x - 4) (y + 3)
(x - 4) (y + 3) =xy <=> 3x - 4y = 12 ----(ii)
Solving (i) and (ii), we get x = 16 and y = 9.
Perimeter of the rectangle = 2 (x + y) = [2 (16 + 9)] cm = 50 cm.
Correct Answer: 140
Explanation:
distance covered in 1 revolution =
= 2 x (22/7) x 20 = 880/7 cm
required no of revolutions = 17600 x (7/880) = 140
Correct Answer: 14
Explanation:
Distance covered in one revolution = = 88m.
Correct Answer: 20ft
Explanation:
let the radius of the pool be Rft
Radius of the pool including the wall = (R+4)ft
Area of the concrete wall = = sq feet
=> 8
Radius of the pool R = 20ft
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