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- Question
The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
Options- A. 20
- B. 200
- C. 300
- D. 400
- Correct Answer
- 200
ExplanationLet length of plot = L meters, then breadth = L - 20 meters
and perimeter = 2[L + L - 20] = [4L - 40] meters
[4L - 40] * 26.50 = 5300
[4L - 40] = 5300 / 26.50 = 200
4L = 240
L = 240/4= 60 meters.
- 1. The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 19 cm. If the area of the trapezium is 475 find the lengths of the parallel sides.
Options- A. 27 and 23
- B. 24 and 23
- C. 25 and 23
- D. 22 and 23 Discuss
- 2. The sides of a right-angled triangle are 12 cm, 16 cm, 20 cm respectively. A new right angle Δ is made by joining the midpoints of all the sides. This process continues for infinite then calculate the sum of the areas of all the triangles so made.
Options- A. 312 sq.cm
- B. 128 sq.cm
- C. 412 sq.cm
- D. 246 sq.cm Discuss
- 3. The area of the circle is 220 sq.m, the area of the square inscribed in a circle will be
Options- A. 49
- B. 70
- C. 140
- D. 150 Discuss
- 4. Find the area of the trapezium, whose parallel sides are 12 cm and 10 cm, and distance between the parallel sides is 14 cm?
Options- A. 121 sq.com
- B. 154 sq.com
- C. 186 sq.com
- D. 164 sq.com Discuss
- 5. Square units 13 by 9 of an office area is
Options- A. 97
- B. 117
- C. 107
- D. 127 Discuss
- 6. A room is 15 feet long and 12 feet broad. A mat has to be placed on the floor of the room leaving 1.5 feet space from the walls. What will be the cost of the mat at the rate of Rs. 3.50 per squire feet?
Options- A. 378
- B. 472.5
- C. 496
- D. 630 Discuss
- 7. Find the ratio of the areas of the incircle and circumcircle of a square ?
Options- A. 1 : 4
- B. 4 : 1
- C. 2 : 1
- D. 1 : 2 Discuss
- 8. The perimeter of a rectangle whose length is 6 m more than its breadth is 84 m. What will be the area of the rectangle?
Options- A. 333 sq.mts
- B. 330 sq.mts
- C. 362 sq.mts
- D. 432 sq.mts Discuss
- 9. What is the least number of squares tiles required to pave the floor of a room 15.17 m long and 9.02 m broad?
Options- A. 814
- B. 714
- C. 614
- D. 713 Discuss
- 10. A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed?
Options- A. 56m
- B. 65m
- C. 34m
- D. 36m Discuss
Area problems
Search Results
Correct Answer: 27 and 23
Explanation:
Let the two parallel sides of the trapezium be a cm and b cm.
Then, a - b = 4
And,
Solving (i) and (ii), we get: a = 27, b = 23.
So, the two parallel sides are 27 cm and 23 cm.
Correct Answer: 128 sq.cm
Correct Answer: 140
Explanation:
area of a square =
Correct Answer: 154 sq.com
Explanation:
We know that,
Area of trapezium = 1/2 x (Sum of parallel sides) x (Distance between Parallel sides)
= 1/2 x (12 + 10) x 14
= 22 x 14/2
= 22 x 7
= 154 sq. cm
Correct Answer: 117
Explanation:
Square units 13 by 9 of an office means office of length 13 units and breadth 9 units.
Now its area is 13x 9 = 117 square units or units square.
Correct Answer: 378
Correct Answer: 1 : 2
Correct Answer: 432 sq.mts
Explanation:
Let the breadth of the rectangle = b mts
Then Length of the rectangle = b + 6 mts
Given perimeter = 84 mts
2(L + B) = 84 mts
2(b+6 + b) = 84
2(2b + 6) = 84
4b + 12 = 84
4b = 84 - 12
4b = 72
b = 18 mts
=> Length = b + 6 = 18 + 6 = 24 mts
Now, required Area of the rectangle = L x B = 24 x 18 = 432 sq. mts
Correct Answer: 814
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile =
Required number of tiles = = 814
Correct Answer: 56m
Explanation:
Length of the wire fencing = perimeter = 2(90 + 50) = 280 metres
Two poles will be kept 5 metres apart. Also remember that the poles will be placed along the perimeter of the rectangular plot, not in a single straight line which is very important.
Hence number of poles required = 280 / 5 = 56
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