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- Question
A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is
Options- A. rs.58
- B. rs.158
- C. rs.258
- D. rs.358
- Correct Answer
- rs.258
Explanationarea of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m
cost of graveling = 344 x (75/100) = Rs. 258
- 1. A man runs round a circular field of radius 50m at the speed of 12 km/hr. What is the time taken by the man to take twenty rounds of the field?
Options- A. 220/7 min
- B. 110/7 min
- C. 90/7 min
- D. 230/7 min Discuss
- 2. A room is half as long again as it is broad. The cost of carpeting the at Rs. 5 per sq.m is Rs. 270 and the cost of papering the four walls at Rs. 10 per sq.m is Rs. 1720. If a door and 2 windows occupy 8 sq. m, find the dimensions of the room.
Options- A. b=6; l=18; H=6
- B. b=5; l=6; H=18
- C. l=6; b=18; H=15
- D. l=5; b=18; H=18 Discuss
- 3. The question given below contain two statements giving certain data. You have to decide whether the data given in the statements are sufficient for answering the question ? Question : What is the height of a right-angled triangle ? Statements : A. The area of the triangle is 20 times its base. B. The perimeter of the triangle is equal to that of a square of the side 10 cm.
Options- A. Only statement A is required
- B. Only statement B is required
- C. Both A & B are required
- D. Neither (A) nor (B) is reuired Discuss
- 4. The area of a square is equal to the area of a rectangle. The length of the rectangle is 5 cm more than a side of the square and its breadth is 3 cm less than the side of the square. What is the perimeter of the rectangle ?
Options- A. 15 cm
- B. 18 cm
- C. 34 cm
- D. 26 cm Discuss
- 5. The base of a parallelogram is twice its height. If the area of the parallelogram is 72 sq. cm, find its height
Options- A. 6
- B. 7
- C. 8
- D. 9 Discuss
- 6. The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m
Options- A. 53800
- B. 43800
- C. 83800
- D. 73800 Discuss
- 7. The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 800 per sq.metre.
Options- A. Rs.15500
- B. Rs.16500
- C. Rs.17500
- D. Rs.18500 Discuss
- 8. The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
Options- A. 2520
- B. 2420
- C. 2320
- D. 2620 Discuss
- 9. The inner circumference of a circular race track, 14 m wide, is 440 m. Find radius of the outer circle
Options- A. 44
- B. 22
- C. 33
- D. 84 Discuss
- 10. The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq.cm. Find the length of the rectangle?
Options- A. 10cm
- B. 20cm
- C. 30cm
- D. 40cm Discuss
Area problems
Search Results
Correct Answer: 220/7 min
Explanation:
speed = 12 km/h =
distance covered =
time taken = distance /speed =
Correct Answer: b=6; l=18; H=6
Explanation:
Let breadth = x metres, length = 3x metres, height = H metres.
Area of the floor=(Total cost of carpeting)/(Rate) = (270/5) sq.m = 54 sq.m
So, breadth = 6 m and length = = 9 m.
Now, papered area = (1720/10) = 172 sq.m
Area of 1 door and 2 windows = 8 sq.m
Total area of 4 walls = (172 + 8) sq.m = 180 sq.m
Correct Answer: Only statement A is required
Explanation:
From statement (A),
20b = (1/2) × b × h
h = 40 cm.
Correct Answer: 34 cm
Explanation:
Let the side of the square be 's' cm
length of rectangle = (s+5) cm
breadth of rectangle = (s-3)cm
(s+5) (s-3) =
- 5s - 3s - 15 =
2s = 15
Perimeter of rectangle = 2(L+B) = 2(s+5 + s?3) = 2(2s + 2)
= 2(15 + 2) = 34 cm
Correct Answer: 6
Explanation:
Let the height of the parallelogram be x. cm. Then, base = (2x) cm.
Correct Answer: 73800
Explanation:
perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800
Correct Answer: Rs.16500
Explanation:
Area = 5.5 × 3.75 sq. metre.
Cost for 1 sq. metre. = Rs. 800
Hence total cost = 5.5 × 3.75 × 800 = 5.5 × 3000 = Rs. 16500
Correct Answer: 2520
Explanation:
We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.
Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) = 2520 sq.m
Correct Answer: 84
Explanation:
Let inner radius be r metres. Then, 2 r = 440 ; r = = 70 m.
Radius of outer circle = (70 + 14) m = 84 m.
Correct Answer: 20cm
Explanation:
Let the breadth of the given rectangle be x then length is 2x.
thus area of the given rect is
after dec 5cm from length and inc 5cm breadth , new lenght becomes 2x-5 and breadth is x+5.thus new area =(2x-5)(x+5)=
since new area is 75 units greater than original area thus
5x=75+25
5x=100
therefore x=20
hence length of the rectangle is 40 cm.
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