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- Question
A room is half as long again as it is broad. The cost of carpeting the at Rs. 5 per sq.m is Rs. 270 and the cost of papering the four walls at Rs. 10 per sq.m is Rs. 1720. If a door and 2 windows occupy 8 sq. m, find the dimensions of the room.
Options- A. b=6; l=18; H=6
- B. b=5; l=6; H=18
- C. l=6; b=18; H=15
- D. l=5; b=18; H=18
- Correct Answer
- b=6; l=18; H=6
ExplanationLet breadth = x metres, length = 3x metres, height = H metres.
Area of the floor=(Total cost of carpeting)/(Rate) = (270/5) sq.m = 54 sq.m
So, breadth = 6 m and length = = 9 m.
Now, papered area = (1720/10) = 172 sq.m
Area of 1 door and 2 windows = 8 sq.m
Total area of 4 walls = (172 + 8) sq.m = 180 sq.m
- 1. The question given below contain two statements giving certain data. You have to decide whether the data given in the statements are sufficient for answering the question ? Question : What is the height of a right-angled triangle ? Statements : A. The area of the triangle is 20 times its base. B. The perimeter of the triangle is equal to that of a square of the side 10 cm.
Options- A. Only statement A is required
- B. Only statement B is required
- C. Both A & B are required
- D. Neither (A) nor (B) is reuired Discuss
- 2. The area of a square is equal to the area of a rectangle. The length of the rectangle is 5 cm more than a side of the square and its breadth is 3 cm less than the side of the square. What is the perimeter of the rectangle ?
Options- A. 15 cm
- B. 18 cm
- C. 34 cm
- D. 26 cm Discuss
- 3. The base of a parallelogram is twice its height. If the area of the parallelogram is 72 sq. cm, find its height
Options- A. 6
- B. 7
- C. 8
- D. 9 Discuss
- 4. Area of a square and a rectangle are equal. If side of the square is 40 cm and length of the rectangle is 64 cm, what is the perimeter of the rectangle ?
Options- A. 187 cm
- B. 178 cm
- C. 149 cm
- D. 194 cm Discuss
- 5. The ratio between the length and breadth of a rectangular field is 5 : 4 if the breadth is 20m less than the length, the perimeter of the field is :
Options- A. 260m
- B. 280m
- C. 360m
- D. none of these Discuss
- 6. A man runs round a circular field of radius 50m at the speed of 12 km/hr. What is the time taken by the man to take twenty rounds of the field?
Options- A. 220/7 min
- B. 110/7 min
- C. 90/7 min
- D. 230/7 min Discuss
- 7. A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is
Options- A. rs.58
- B. rs.158
- C. rs.258
- D. rs.358 Discuss
- 8. The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m
Options- A. 53800
- B. 43800
- C. 83800
- D. 73800 Discuss
- 9. The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 800 per sq.metre.
Options- A. Rs.15500
- B. Rs.16500
- C. Rs.17500
- D. Rs.18500 Discuss
- 10. The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
Options- A. 2520
- B. 2420
- C. 2320
- D. 2620 Discuss
Area problems
Search Results
Correct Answer: Only statement A is required
Explanation:
From statement (A),
20b = (1/2) × b × h
h = 40 cm.
Correct Answer: 34 cm
Explanation:
Let the side of the square be 's' cm
length of rectangle = (s+5) cm
breadth of rectangle = (s-3)cm
(s+5) (s-3) =
- 5s - 3s - 15 =
2s = 15
Perimeter of rectangle = 2(L+B) = 2(s+5 + s?3) = 2(2s + 2)
= 2(15 + 2) = 34 cm
Correct Answer: 6
Explanation:
Let the height of the parallelogram be x. cm. Then, base = (2x) cm.
Correct Answer: 178 cm
Explanation:
Area of square = 40 x 40
= 1600 sq.cm
Given that the areas of Square and Rectangle are equal
=> Area of rectangle = 1600 Sq.cm
We know that, Area of rectangle = L x B
Given L = 64 cm
Breadth of rectangle = 1600/64 = 25 cm
Perimeter of the rectangle = 2(L + B) = 2(64+25) = 178 cm.
Correct Answer:
Correct Answer: 220/7 min
Explanation:
speed = 12 km/h =
distance covered =
time taken = distance /speed =
Correct Answer: rs.258
Explanation:
area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m
cost of graveling = 344 x (75/100) = Rs. 258
Correct Answer: 73800
Explanation:
perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800
Correct Answer: Rs.16500
Explanation:
Area = 5.5 × 3.75 sq. metre.
Cost for 1 sq. metre. = Rs. 800
Hence total cost = 5.5 × 3.75 × 800 = 5.5 × 3000 = Rs. 16500
Correct Answer: 2520
Explanation:
We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.
Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) = 2520 sq.m
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