=> 2l + 2b = 5b => 3b = 2l
b=(2/3)l
Then, Area = 216 cm2
=> l x b = 216 => l x (2/3)l =216
l = 18 cm.
100 cm is read as 102 cm.
A1 = (100*100)Sq.cm
A2 = (102*102)Sq.cm
(A2 - A1) = = (102 + 100) x (102 - 100) = 404 sq.cm.
Let the breadth of floor be 'b' m.
Then, length of the floor is 'l = (b + 25)'
Area of the rectangular floor = l x b = (b + 25) × b
According to the question,
(b + 15) (b + 8) = (b + 25) × b
2b = 120
b = 60 m.
l = b + 25 = 60 + 25 = 85 m.
Area of the floor = 85 × 60 = 5100 sq.m.
Let original length = x and original breadth = y.
Original area = xy.
New length = x/2 and New breadth=3y
New area =
Therefore, Increase in area = New area-original area =
Therefore, Increase % = %
Let a = 13, b = 14 and c = 15. Then, =21
(s- a) = 8, (s - b) = 7 and (s - c) = 6.
Area =
=
= 84 sq.cm
area of the room = 544 x 374 sq.cm
size of largest square tile = H.C.F of 544cm and 374 cm= 34 cm
area of 1 tile = 34x34 sq cm
no. of tiles required = (544 x 374) / (34 x 34) = 176
required area = (area of an equilateral triangle of side 7 cm)- (3 * area of sector with à = 60 degrees and r = 3.5cm)
sq cm
= sq cm
= 1.967 sq cm
Area of 4 walls = 2(l+b)h
=2(10+7) x 5 = 170 sq m
Area of 2 doors and 3 windows = 2(1x3)+(2x1.5)+2(1x1.5) = 12 sq m
area to be planted = 170 -12 = 158 sq m
Cost of painting = Rs. 158 x 3 = Rs. 474
Area of square = 40 x 40
= 1600 sq.cm
Given that the areas of Square and Rectangle are equal
=> Area of rectangle = 1600 Sq.cm
We know that, Area of rectangle = L x B
Given L = 64 cm
Breadth of rectangle = 1600/64 = 25 cm
Perimeter of the rectangle = 2(L + B) = 2(64+25) = 178 cm.
Let the height of the parallelogram be x. cm. Then, base = (2x) cm.
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