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- Question
A room of 5m 44cm long and 3m 74cm broad is to be paved with squre tiles. Find the least number of squre tiles required to cover the floor.
Options- A. 136
- B. 146
- C. 166
- D. 176
- Correct Answer
- 176
Explanationarea of the room = 544 x 374 sq.cm
size of largest square tile = H.C.F of 544cm and 374 cm= 34 cm
area of 1 tile = 34x34 sq cm
no. of tiles required = (544 x 374) / (34 x 34) = 176
- 1. The diameter of the driving wheel of a bus is 140 cm. How many revolution, per minute must the wheel make in order to keep a speed of 66 kmph ?
Options- A. 150
- B. 250
- C. 350
- D. 550 Discuss
- 2. The length of a rectangle is twice its breadth if its length is decreased by 5cm and breadth is increased by 5cm, the area of the rectangle is increased by 75 sq cm. Find the length of the rectangle.
Options- A. 30
- B. 40
- C. 50
- D. 60 Discuss
- 3. Find the area of a right-angled triangle whose base is 12 cm and hypotenuse is 13cm.
Options- A. 30
- B. 40
- C. 50
- D. 60 Discuss
- 4. A room 5m 55cm long and 3m 74cm broad is to be paved with square tiles.Find the least number of square tiles required to cover the floor?
Options- A. 156
- B. 166
- C. 176
- D. 186 Discuss
- 5. The ratios of areas of two squares, one having its diagonal double than the other is
Options- A. 2:1
- B. 2:3
- C. 3:1
- D. 4:1 Discuss
- 6. Find the area of a triangle whose sides measure 13 cm, 14 cm and 15 cm.
Options- A. 84
- B. 64
- C. 44
- D. 22 Discuss
- 7. The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?
Options- A. 20%
- B. 30%
- C. 40%
- D. 50% Discuss
- 8. The length of a class room floor exceeds its breadth by 25 m. The area of the floor remains unchanged when the length is decreased by 10 m but the breadth is increased by 8 m. The area of the floor is
Options- A. 5100 sq.m
- B. 4870 sq.m
- C. 4987 sq.m
- D. 4442 sq.m Discuss
- 9. An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:
Options- A. 1.04
- B. 2.04
- C. 3.04
- D. 4.04 Discuss
- 10. The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?
Options- A. 16
- B. 18
- C. 20
- D. 22 Discuss
Area problems
Search Results
Correct Answer: 250
Explanation:
Circumference = No.of revolutions * Distance covered
Distance to be covered in 1 min. = (66 X1000)/60 m = 1100 m.
Circumference of the wheel = 2 x (22/7) x 0.70 m = 4.4 m.
Number of revolutions per min. =(1100/4.4) = 250.
Correct Answer: 40
Explanation:
let length = 2x and breadth = x then
(2x-5) (x+5) = (2x * x)+75
5x-25 = 75 => x=20
length of the rectangle = 40 cm
Correct Answer: 30
Explanation:
Height of the triangle = = 5 cm.
Its area = = = .
Correct Answer: 176
Explanation:
Area of the room=(544 * 374)
size of largest square tile= H.C.F of 544 & 374 = 34 cm
Area of 1 tile = (34 x 34)
Number of tiles required== [(544 x 374) / (34 x 34)] = 176
Correct Answer: 4:1
Explanation:
ratio =
Correct Answer: 84
Explanation:
Let a = 13, b = 14 and c = 15. Then, =21
(s- a) = 8, (s - b) = 7 and (s - c) = 6.
Area =
=
= 84 sq.cm
Correct Answer: 50%
Explanation:
Let original length = x and original breadth = y.
Original area = xy.
New length = x/2 and New breadth=3y
New area =
Therefore, Increase in area = New area-original area =
Therefore, Increase % = %
Correct Answer: 5100 sq.m
Explanation:
Let the breadth of floor be 'b' m.
Then, length of the floor is 'l = (b + 25)'
Area of the rectangular floor = l x b = (b + 25) × b
According to the question,
(b + 15) (b + 8) = (b + 25) × b
2b = 120
b = 60 m.
l = b + 25 = 60 + 25 = 85 m.
Area of the floor = 85 × 60 = 5100 sq.m.
Correct Answer: 4.04
Explanation:
100 cm is read as 102 cm.
A1 = (100*100)Sq.cm
A2 = (102*102)Sq.cm
(A2 - A1) = = (102 + 100) x (102 - 100) = 404 sq.cm.
Correct Answer: 18
Explanation:
=> 2l + 2b = 5b => 3b = 2l
b=(2/3)l
Then, Area = 216 cm2
=> l x b = 216 => l x (2/3)l =216
l = 18 cm.
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