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- Question
The ratios of areas of two squares, one having its diagonal double than the other is
Options- A. 2:1
- B. 2:3
- C. 3:1
- D. 4:1
- Correct Answer
- 4:1
Explanationratio =
- 1. The base of a parallelogram is twice its height. If the area of the parallelogram is 72 sq.cm. Find its height?
Options- A. 3 cm
- B. 4 cm
- C. 6 cm
- D. 8 cm Discuss
- 2. A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is
Options- A. Rs. 258
- B. Rs. 358
- C. Rs. 458
- D. Rs. 558 Discuss
- 3. The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.
Options- A. B=900;H=300
- B. B=300;H=900
- C. B=600;H=700
- D. B=500;H=900 Discuss
- 4. A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Options- A. 1
- B. 2
- C. 3
- D. 4 Discuss
- 5. The length of a rectangular hall is 5m more than its breadth. The area of the hall is 750 sq.m. The length of the hall is
Options- A. 20
- B. 25
- C. 30
- D. 35 Discuss
- 6. A room 5m 55cm long and 3m 74cm broad is to be paved with square tiles.Find the least number of square tiles required to cover the floor?
Options- A. 156
- B. 166
- C. 176
- D. 186 Discuss
- 7. Find the area of a right-angled triangle whose base is 12 cm and hypotenuse is 13cm.
Options- A. 30
- B. 40
- C. 50
- D. 60 Discuss
- 8. The length of a rectangle is twice its breadth if its length is decreased by 5cm and breadth is increased by 5cm, the area of the rectangle is increased by 75 sq cm. Find the length of the rectangle.
Options- A. 30
- B. 40
- C. 50
- D. 60 Discuss
- 9. The diameter of the driving wheel of a bus is 140 cm. How many revolution, per minute must the wheel make in order to keep a speed of 66 kmph ?
Options- A. 150
- B. 250
- C. 350
- D. 550 Discuss
- 10. A room of 5m 44cm long and 3m 74cm broad is to be paved with squre tiles. Find the least number of squre tiles required to cover the floor.
Options- A. 136
- B. 146
- C. 166
- D. 176 Discuss
Area problems
Search Results
Correct Answer: 6 cm
Explanation:
Let height =x Then, base =2x
2x * x = 72
=>x=6
Correct Answer: Rs. 558
Explanation:
Area to be plastered =
=
Cost of plastering =
Correct Answer: B=900;H=300
Explanation:
Area of the field = Total cost/rate = (333.18/25.6) = 13.5 hectares
Let altitude = x metres and base = 3x metres.
Then,
Base = 900 m and Altitude = 300 m.
Correct Answer: 3
Explanation:
Area of the park = (60 x 40) = 2400
Area of the lawn = 2109
Area of the crossroads = (2400 - 2109) = 291
Let the width of the road be x metres. Then,
(x - 97)(x - 3) = 0
x = 3.
Correct Answer: 30
Explanation:
Let breadth = x m
Then, length = (x+5)m
Area of a rectangle = Length x Breadth
x(x+5) = 750
x² + 5x - 750= 0
(x+30)(x-25)= 0
x = 25 or x = -30
Hence, breadth x = 25m
=> Length = x + 5 = 25 + 5 = 30m.
Correct Answer: 176
Explanation:
Area of the room=(544 * 374)
size of largest square tile= H.C.F of 544 & 374 = 34 cm
Area of 1 tile = (34 x 34)
Number of tiles required== [(544 x 374) / (34 x 34)] = 176
Correct Answer: 30
Explanation:
Height of the triangle = = 5 cm.
Its area = = = .
Correct Answer: 40
Explanation:
let length = 2x and breadth = x then
(2x-5) (x+5) = (2x * x)+75
5x-25 = 75 => x=20
length of the rectangle = 40 cm
Correct Answer: 250
Explanation:
Circumference = No.of revolutions * Distance covered
Distance to be covered in 1 min. = (66 X1000)/60 m = 1100 m.
Circumference of the wheel = 2 x (22/7) x 0.70 m = 4.4 m.
Number of revolutions per min. =(1100/4.4) = 250.
Correct Answer: 176
Explanation:
area of the room = 544 x 374 sq.cm
size of largest square tile = H.C.F of 544cm and 374 cm= 34 cm
area of 1 tile = 34x34 sq cm
no. of tiles required = (544 x 374) / (34 x 34) = 176
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