let ABC be the isosceles triangle, the AD be the altitude
Let AB = AC = x then BC= 32-2x [because parameter = 2 (side) + Base]
since in an isoceles triange the altitude bisects the base so
BD = DC = 16-x
In a triangle ADC,
BC = 32-2x = 32-20 = 12 cm
Hence, required area = = = 60 sq cm
The shaded region represents
y ? x
Let 45 x A = (25 x 900)/100
? A = (25 x 9)/45 = 5
CP = [100/(100 - Loss%) ] x SP
CP = 6000 x (100/75) = 8000
NA
Angle swept in 30 min= 180°
Area swept = [(22/7) x 7 x 7] x [180°/360°] cm2
= 77 cm2
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