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- Question
A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be
Options- A. 7744
- B. 8844
- C. 5544
- D. 4444
- Correct Answer
- 7744
Explanationlength of wire = = 2 x (22/7 ) x 56 = 352 cm
side of the square = 352/4 = 88cm
area of the square = 88 x 88 = 7744sq cm - 1. Find the ratio of the areas of the incircle and circumcircle of a square.
Options- A. 1:1
- B. 1:2
- C. 1:3
- D. 1:4 Discuss
- 2. A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
Options- A. 30
- B. 40
- C. 50
- D. 60 Discuss
- 3. The percentage increase in the area of a rectangle, if each of its sides is increased by 20%
Options- A. 22%
- B. 33%
- C. 44%
- D. 55% Discuss
- 4. A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is
Options- A. 136
- B. 236
- C. 336
- D. 436 Discuss
- 5. The diagonal of a rectangle is 41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be:
Options- A. 18
- B. 28
- C. 38
- D. 48 Discuss
- 6. The ratio of the area of a square to that of the square drawn on its diagonal is
Options- A. 1:2
- B. 2;3
- C. 3:1
- D. 4:1 Discuss
- 7. The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is
Options- A. 49
- B. 154
- C. 378
- D. 1078 Discuss
- 8. One side of a rectangular field is 15m and one of its diagonal is 17m. Find the area of field?
Options- A. 110
- B. 120
- C. 130
- D. 140 Discuss
- 9. The altitude drawn to the base of an isosceles triangle is 8cm and the perimeter is 32cm. Find the area of the triangle?
Options- A. 50
- B. 60
- C. 70
- D. 80 Discuss
- 10. If the length of the diagonal of a square is 20cm,then its perimeter must be a. 402 cm b. 302 cm c. 10cm d. 15 2 cm
Options- A. a
- B. b
- C. c
- D. d Discuss
Area problems
Search Results
Correct Answer: 1:2
Explanation:
Let the side of the square be x. Then, its diagonal =
Radius of incircle =
Radius of circum circle=
Required ratio =
Correct Answer: 30
Explanation:
Let the side of the square(ABCD) be x meters.
Then, AB + BC = 2x metres.
AC = = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = = 30% (approx)
Correct Answer: 44%
Explanation:
Let original length = x metres and original breadth = y metres.
Original area = xy sq.m
Increased length = and Increased breadth =
New area =
The difference between the Original area and New area is:
Increase % = = 44%
Correct Answer: 336
Explanation:
let ABCD be the given parallelogram
area of parallelogram ABCD = 2 x (area of triangle ABC)
now a = 30m, b = 14m and c = 40m
s=1/2 x (30+14+40) = 42
Area of triangle ABC =
= = 168sq m
area of parallelogram ABCD = 2 x 168 = 336 sq m
Correct Answer: 18
Explanation:
(or)
Also,
= 41 + 40 = 81
(l + b) = 9.
Perimeter = 2(l + b) = 18 cm.
Correct Answer: 1:2
Explanation:
ratio =
Correct Answer: 154
Explanation:
The diameter is equal to the shortest side of the rectangle.
So radius= 14/2 = 7cm.
Therefore,
Correct Answer: 120
Explanation:
Other side = [(17 x 17) - (15 x 15)] = (289 - 225) = 8m
Area = 15 x 8 =120 sq. m
Correct Answer: 60
Explanation:
let ABC be the isosceles triangle, the AD be the altitude
Let AB = AC = x then BC= 32-2x [because parameter = 2 (side) + Base]
since in an isoceles triange the altitude bisects the base so
BD = DC = 16-x
In a triangle ADC,
BC = 32-2x = 32-20 = 12 cm
Hence, required area = = = 60 sq cm
Correct Answer: a
Explanation:
We know that d=?2s
Given diagonal = 20 cm
=> s = 20/ cm
Therefore, perimeter of the square is 4s = 4 x 20/ = 40 cm.
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