Amount of pure milk= a(1 ?b/a)n(n = 3, a = pure milk and b = amount replaced)= 960 (1 ?48/960)^3= 960(1-1/20)^3= 960 * 19/20 * 19/20*19/20= 823.08 lt.
let each side of the square be a , then area =
As given that The side is increased by 25%, then
New side = 125a/100 = 5a/4
New area =
Increased area=
Increase %= % = 56.25%
let length = x and breadth = y then
2(x+y) = 46 => x+y = 23
x²+y² = 17² = 289
now (x+y)² = 23²
=> x²+y²+2xy= 529
=> 289+ 2xy = 529
=> xy = 120
area = xy = 120 sq.cm
Let original radius = R.
New radius = =
Original area = and new area =
Decrease in area = = 75%
(or)
Also,
= 41 + 40 = 81
(l + b) = 9.
Perimeter = 2(l + b) = 18 cm.
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