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- Question
In a mixture of 240 lt. water is 20% and rest is Milk. What quantity of mixture should be taken out and replaced with water so that water becomes 40%?
Options- A. 60 lit
- B. 55 lit
- C. 45 lit
- D. 50 lit
- Correct Answer
- 60 lit
- 1. From the 50 liters of milk, 5 liters of milk is taken out and after it 5 liters of water is added to the rest amount of milk. Again 5 liters of milk and water is drawn out and it was replaced by 5 liters of water. If this process is continued similarly for the third time, the amount of milk left after the third replacement:
Options- A. 45L
- B. 36.45L
- C. 40.5L
- D. 42.5L Discuss
- 2. In what ratio must a merchant mix two varieties of oils worth Rs. 60/kg and Rs. 65/kg, so that by selling the mixture at Rs. 68.20/kg, he may gain 10% ?
Options- A. 2:3
- B. 4:3
- C. 3:4
- D. 3:2 Discuss
- 3. From a tank of petrol , which contains 200 liters of petrol, the seller replaces each time with kerosene when he sells 40 liters of petrol(or mixture). Everytime he sells out only 40 liters of petrol (pure or impure). After replacing the petrol with kerosene 4th time, the total amount of kerosene in the mixture is
Options- A. 81.92L
- B. 96L
- C. 118.08L
- D. None of these Discuss
- 4. There are two mixtures of honey and water in which the ratio of honey and water are as 1:3 and 3:1 respectively. Two litres are drawn from first mixture and 3 litres from second mixture, are mixed to form another mixture. What is the ratio of honey and water in it ?
Options- A. 111:108
- B. 11:9
- C. 103:72
- D. None Discuss
- 5. A milkman has 20 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk. If the cost of pure milk is Rs. 18 per litre, then the profit of the milkman, when he sells all the mixture at cost price, the profit % ?
Options- A. 22.5%
- B. 25%
- C. 20%
- D. 33.33% Discuss
- 6. A container contains 120 lit of Diesel. From this container, 12 lit of Diesel was taken out and replaced by kerosene. This process was further repeated for two times. How much diesel is now there in the container ?
Options- A. 88.01 lit
- B. 87.48 lit
- C. 87.51 lit
- D. 87.62 lit Discuss
- 7. An alloy contains gold and silver in the ratio 5 : 8 and another alloy contains gold and silver in the ratio 5 : 3. If equal amount of both the alloys are melted together, then the ratio of gold and silver in the resulting alloy is ?
Options- A. 113/108
- B. 105/103
- C. 108/115
- D. 103/113 Discuss
- 8. In a 100 litre of mixture the ratio of milk and water is 6:4. How much milk must be added to the mixture in order to make the ratio 3 : 1?
Options- A. 85
- B. 60
- C. 55
- D. 45 Discuss
- 9. If a man buys 1 lt of milk for Rs.12 and mixes it with 20% water and sells it for Rs.15, then what is the percentage of gain ?
Options- A. 25%
- B. 30%
- C. 17%
- D. 19% Discuss
- 10. Manideep purchases 30kg of barley at the rate of 11.50/kg and 20kg at the rate of 14.25/kg. He mixed the two and sold the mixture in the shop. At what price per kg should he sell the mixture to make 30% profit to him ?
Options- A. 15.84
- B. 14.92
- C. 13.98
- D. 16.38 Discuss
Alligation or Mixture problems
Search Results
Correct Answer: 36.45L
Explanation:
General Formula:
Final or reduced concentration = initial concentration x
where n is the number of times the same operation is being repeated. The "amount being replaced" could be pure or mixture as per the case. similarly ,"total amount" could also be either pure or mixture. Here amount being replaced denotes the quantity which is to be withdrawn in each time.
Therefore,
= 36.45 L
Correct Answer: 3:2
Explanation:
Let he mixes the oils in the ratio = x : y
Then, the cost price of the oils = 60x + 65y
Given selling price = Rs. 68.20
=> Selling price = 68.20(x+y)
Given profit = 10% = SP - CP
=> 10/100 (60x + 65y) = 68.20(x+y)-(60x + 65y)
=> 6x + 6.5y = 8.20x + 3.20y
=>2.2x = 3.3y
=> x : y = 3 : 2
Correct Answer: 118.08L
Explanation:
The amount of petrol left after 4 operations = 81.92
Hence the amount of kerosene = 200 - 81.92 = 118.08 liters
Correct Answer: 11:9
Explanation:
From the given data,
The part of honey in the first mixture = 1/4
The part of honey in the second mixture = 3/4
Let the part of honey in the third mixture = x
Then,
1/4 3/4
x
(3/4)-x x-(1/4)
Given from mixtures 1 & 2 the ratio of mixture taken out is 2 : 3
=>
=> Solving we get the part of honey in the third mixture as 11/20
=> the remaining part of the mixture is water = 9/20
Hence, the ratio of the mixture of honey and water in the third mixture is 11 : 9 .
Correct Answer: 25%
Explanation:
As water costs free, water sold at cost price of milk gives the profit.
Required profit % = 5/20 x 100 = 5 x 5 = 25%.
Correct Answer: 87.48 lit
Explanation:
For these type of problems,
Quantity of Diesel remained =
Here p = 12 , q = 120
=> = 120 x 0.9 x 0.9 x 0.9 = 87.48 lit.
Correct Answer: 105/103
Explanation:
As given equal amounts of alloys are melted, let it be 1 kg.
Required ratio of gold and silver =
Hence, ratio of gold and silver in the resulting alloy = 105/103.
Correct Answer: 60
Explanation:
Let M litres milk be added
=>
=> 60 + M = 120
=> M = 60 lit.
Correct Answer: 25%
Explanation:
He has gain = 15 - 12 = 3,
Gain% = (3/12) x 100 = (100/4) = 25.
He has 25% gain.
Correct Answer: 16.38
Explanation:
Given, Manideep purchases 30kg of barley at the rate of 11.50/kg nad 20kg at the rate of 14.25/kg.
Total cost of the mixture of barley = (30 x 11.50) + (20 x 14.25)
=> Total cost of the mixture = Rs. 630
Total kgs of the mixture = 30 + 20 = 50kg
Cost of mixture/kg = 630/50 = 12.6/kg
To make 30% of profit
=> Selling price for manideep = 12.6 + 30% x 12.6
=> Selling price for manideep = 12.6 + 3.78 = 16.38/kg.
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