A jar was full with honey. A person used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar solution. The initial amount of honey in the jar was filled with the sugar solution. The initial amount of honey in the jar was:

Correct Answer: 32 lit

Explanation:

Given mixture = 48 lit

Milk in it = 48 x 5/8 = 30 lit

=> Water in it = 48 - 30 = 18 lit

Let 'L' lit of water is added to make the ratio as 3:5

=> 30/(18+L) = 3/5

=> 150 = 54 + 3L

=> L = 32 lit.

Correct Answer: 80%

Explanation:

Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm.

 

After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm.

 

So % of water = 100 x 60/75 = 80%.

Correct Answer: 50 l

Explanation:

Let the tin contain 5x litres of liquids

5 x - 45 x 4 5 5 x - 45 x 1 5 + 45 = 2 5

=> 5(4x - 36) = 2(x + 36)

=> 20x - 180 = 2x + 72

=> x = 14 litres

Hence, the initial quantity of mixture = 70l

Quantity of liquid B

=  70 - 45 x 1 5 + 45

= 50 litres.

Correct Answer: 120 litres

Explanation:

w i n e ( l e f t ) w i n e ( a d d e d ) = 343 169

 

It means  w i n e ( l e f t ) w i n e ( i n i t i a l a m o u n t ) = 343 512    (since 343 + 169 = 512)

  

Thus,   343 x = 512 x 1 - 15 k 3

 

  343 512 = 7 8 3 = 1 - 15 k 3

 

  1 - 15 k = 7 8 = 1 - 1 8

  

Thus the initial amount of wine was 120 liters.

Correct Answer: 9:1

Explanation:

Milk = 3/5 x 20 = 12 liters, water = 8 liters

 

If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.

 

Remaining milk = 12 - 6 = 6 liters

Remaining water = 8 - 4 = 4 liters

 

10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.

 

The ratio of milk and water in the new mixture = 16:4 = 4:1

 

If the process is repeated one more time and 10 liters of the mixture are removed,
then amount of milk removed = 4/5 x 10 = 8 liters.

 

Amount of water removed = 2 liters.

 

Remaining milk = (16 - 8) = 8 liters.

Remaining water = (4 -2) = 2 liters.

 

Now 10 lts milk is added => total milk = 18 lts

 

The required ratio of milk and water in the final mixture obtained

 

= (8 + 10):2 = 18:2 = 9:1.

Correct Answer: 1 : 10

Explanation:

Customer ratio of Milk and Water is given by

Milk          ::        Water

  6.4                         0

          8 1 + 3 8 = 64 11

  64 11                       64 10 - 64 11

=> Milk : Water = 110 : 11 = 10 : 1

 

Therefore, the proportionate of Water to Milk for Customer is 1 : 10

Correct Answer: 33.33%

Explanation:

Now, take percentage of milk and applying mixture rule

25          100

       50

50            25  = 2 : 1

 

Hence required answer =  1/3 or 33.33%

Correct Answer: 29.63 litres

Explanation:

Given that container has 50 litres of milk.

 After replacing 8 litres of milk with water for three times, milk contained in the container is:

  ? 50 1 - 8 50 3

? 50 × 42 50 × 42 50 × 42 50  = 29.63 litres.

Correct Answer: 49 : 221

Explanation:

Copper in 4 kg = 4/5 kg          and      Zinc in 4 kg = 4 x (4/5) kg

 

Copper in 5 kg = 5/6 kg          and      Zinc in 5 kg = 5 x (5/6) kg

 

Therefore, Copper in mixture =  4 5 + 5 6 = 49 30 kg

 

and  Zinc in the mixture = 16 5 + 25 6 = 221 30kg

 

Therefore the required ratio = 49 : 221

Correct Answer: 76.92%

Explanation:

Let the milk he bought is 1000 ml

Let C.P of 1000 ml is Rs. 100

Here let he is mixing K ml of water

He is getting 30% profit

=> Now, the selling price is also Rs. 100 for 1000 ml

=> 100 : K%

= 100 : 30

10 : 3 is ratio of milk to water

=> Percentage of milk = 10 x 100/13 = 1000/13 = 76.92%