A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?

Correct Answer: 120 litres

Explanation:

w i n e ( l e f t ) w i n e ( a d d e d ) = 343 169

 

It means  w i n e ( l e f t ) w i n e ( i n i t i a l a m o u n t ) = 343 512    (since 343 + 169 = 512)

  

Thus,   343 x = 512 x 1 - 15 k 3

 

  343 512 = 7 8 3 = 1 - 15 k 3

 

  1 - 15 k = 7 8 = 1 - 1 8

  

Thus the initial amount of wine was 120 liters.

Correct Answer: 9:1

Explanation:

Milk = 3/5 x 20 = 12 liters, water = 8 liters

 

If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.

 

Remaining milk = 12 - 6 = 6 liters

Remaining water = 8 - 4 = 4 liters

 

10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.

 

The ratio of milk and water in the new mixture = 16:4 = 4:1

 

If the process is repeated one more time and 10 liters of the mixture are removed,
then amount of milk removed = 4/5 x 10 = 8 liters.

 

Amount of water removed = 2 liters.

 

Remaining milk = (16 - 8) = 8 liters.

Remaining water = (4 -2) = 2 liters.

 

Now 10 lts milk is added => total milk = 18 lts

 

The required ratio of milk and water in the final mixture obtained

 

= (8 + 10):2 = 18:2 = 9:1.

Correct Answer: 120 liters

Explanation:

W i n e ( l e f t ) W a t e r ( a d d e d ) = 343 169

 

It means    W i n e ( l e f t ) W i n e ( i n i t i a l a m o u n t ) = 343 512   ? 343 + 169 = 512

 

Thus ,       

343 x = 512 x 1 - 15 K 3

 

  ? 343 512 = 7 8 3 = 1 - 15 k 3

 

=> K = 120

Thus the initial amount of wine was 120 liters.

Correct Answer: 80 lit

Explanation:

From the given data,

let the initial quantity of the mixture = 5x

Then,

$$\begin{gathered} 2 x - 16 3 x - 24 + 40 = 1 4 \\ 8 x - 64 = 3 x + 16 \\ 5 x = 80 \\ x = 16 lit \end{gathered}$$

 

Then the initial quantity of the mixture = 5x = 5 x 16 = 80 lit.

Correct Answer: 91 liters

Explanation:

         Milk             Water 

         74%             26%        (initially) 

         76%             24%        ( after replacement) 

 

  Left amount = Initial amount  1 - r e p l a c e d a m o u n t t o t a l a m o u n t 

   24  = 26 1 - 7 k

=> k = 91 

Correct Answer: 80%

Explanation:

Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm.

 

After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm.

 

So % of water = 100 x 60/75 = 80%.

Correct Answer: 32 lit

Explanation:

Given mixture = 48 lit

Milk in it = 48 x 5/8 = 30 lit

=> Water in it = 48 - 30 = 18 lit

Let 'L' lit of water is added to make the ratio as 3:5

=> 30/(18+L) = 3/5

=> 150 = 54 + 3L

=> L = 32 lit.

Correct Answer: 1.25 kg

Explanation:

Let the initial amount of honey in the jar was K, then 

  512 = K 1 - 1 5 4     ? 20 % = 20 100 = 1 5

        or      

512 = K 4 5 4

Therefore, K = 1250

Hence initially the honey in the jar= 1.25 kg

Correct Answer: 1 : 10

Explanation:

Customer ratio of Milk and Water is given by

Milk          ::        Water

  6.4                         0

          8 1 + 3 8 = 64 11

  64 11                       64 10 - 64 11

=> Milk : Water = 110 : 11 = 10 : 1

 

Therefore, the proportionate of Water to Milk for Customer is 1 : 10

Correct Answer: 33.33%

Explanation:

Now, take percentage of milk and applying mixture rule

25          100

       50

50            25  = 2 : 1

 

Hence required answer =  1/3 or 33.33%