A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ?

Correct Answer: 120 liters

Explanation:

W i n e ( l e f t ) W a t e r ( a d d e d ) = 343 169

 

It means    W i n e ( l e f t ) W i n e ( i n i t i a l a m o u n t ) = 343 512   ? 343 + 169 = 512

 

Thus ,       

343 x = 512 x 1 - 15 K 3

 

  ? 343 512 = 7 8 3 = 1 - 15 k 3

 

=> K = 120

Thus the initial amount of wine was 120 liters.

Correct Answer: 80 lit

Explanation:

From the given data,

let the initial quantity of the mixture = 5x

Then,

$$\begin{gathered} 2 x - 16 3 x - 24 + 40 = 1 4 \\ 8 x - 64 = 3 x + 16 \\ 5 x = 80 \\ x = 16 lit \end{gathered}$$

 

Then the initial quantity of the mixture = 5x = 5 x 16 = 80 lit.

Correct Answer: 91 liters

Explanation:

         Milk             Water 

         74%             26%        (initially) 

         76%             24%        ( after replacement) 

 

  Left amount = Initial amount  1 - r e p l a c e d a m o u n t t o t a l a m o u n t 

   24  = 26 1 - 7 k

=> k = 91 

Correct Answer: 22 lit

Explanation:

Let the capacity of the pot be 'P' litres.
Quantity of milk in the mixture before adding milk = 4/9 (P - 8)
After adding milk, quantity of milk in the mixture = 6/11 P.
6P/11 - 8 = 4/9(P - 8)
10P = 792 - 352 => P = 44.

The capacity of the pot is 44 liters.

Correct Answer: 15

Explanation:

Let quantity of mixture be x liters.

 

Suppose a container contains x units of liquid from which y units are taken out and replaced by Water. After operations , the quantity of pure liquid =  x 1 - y x n units, Where n = no of operations . 

 

So, Quantity of Milk =  x 1 - 6 x 2  

 

Given that, Milk : Water = 9 : 16 

 

=> Milk : (Milk + Water) = 9 : (9+16)

 

=> Milk : Mixture = 9 : 25 

 

 Therefore,  x 1 - 6 x 2 x = 9 25

 

=> x = 15 liters

Correct Answer: 120 litres

Explanation:

w i n e ( l e f t ) w i n e ( a d d e d ) = 343 169

 

It means  w i n e ( l e f t ) w i n e ( i n i t i a l a m o u n t ) = 343 512    (since 343 + 169 = 512)

  

Thus,   343 x = 512 x 1 - 15 k 3

 

  343 512 = 7 8 3 = 1 - 15 k 3

 

  1 - 15 k = 7 8 = 1 - 1 8

  

Thus the initial amount of wine was 120 liters.

Correct Answer: 50 l

Explanation:

Let the tin contain 5x litres of liquids

5 x - 45 x 4 5 5 x - 45 x 1 5 + 45 = 2 5

=> 5(4x - 36) = 2(x + 36)

=> 20x - 180 = 2x + 72

=> x = 14 litres

Hence, the initial quantity of mixture = 70l

Quantity of liquid B

=  70 - 45 x 1 5 + 45

= 50 litres.

Correct Answer: 80%

Explanation:

Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm.

 

After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm.

 

So % of water = 100 x 60/75 = 80%.

Correct Answer: 32 lit

Explanation:

Given mixture = 48 lit

Milk in it = 48 x 5/8 = 30 lit

=> Water in it = 48 - 30 = 18 lit

Let 'L' lit of water is added to make the ratio as 3:5

=> 30/(18+L) = 3/5

=> 150 = 54 + 3L

=> L = 32 lit.

Correct Answer: 1.25 kg

Explanation:

Let the initial amount of honey in the jar was K, then 

  512 = K 1 - 1 5 4     ? 20 % = 20 100 = 1 5

        or      

512 = K 4 5 4

Therefore, K = 1250

Hence initially the honey in the jar= 1.25 kg