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- Question
Ratio of water and milk in a container is 2 : 3. If 40 liter mixture removed from the container and same quantity of milk is added to it then the ratio of water to milk becomes 1 : 4. Find the initial quantity of mixture ?
Options- A. 75 lit
- B. 80 lit
- C. 85 lit
- D. 90 lit
- Correct Answer
- 80 lit
ExplanationFrom the given data,
let the initial quantity of the mixture = 5x
Then,
Then the initial quantity of the mixture = 5x = 5 x 16 = 80 lit.
- 1. In a mixture of milk and water, there is only 26% water. After replacing the mixture with 7 liters of pure milk , the percentage of milk in the mixture become 76%. The quantity of mixture is:
Options- A. 65 liters
- B. 91 liters
- C. 38 liters
- D. None of these Discuss
- 2. In a pot, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 8 litres of milk, the pot would be full and ratio of milk and water would become 6 : 5. Find the capacity of the pot ?
Options- A. 11 lit
- B. 22 lit
- C. 33 lit
- D. 44 lit Discuss
- 3. From a container, 6 liters milk was drawn out and was replaced by water. Again 6 liters of mixture was drawn out and was replaced by the water. Thus the quantity of milk and water in the container after these two operations is 9:16. The quantity of mixture is:
Options- A. 15
- B. 16
- C. 25
- D. 31 Discuss
- 4. In the 75 litres of mixture of milk and water, the ratio of milk and water is 4:1. The quantity of water required to make the ratio of milk and water 3:1 is
Options- A. 1 litre
- B. 3 litres
- C. 4 litres
- D. 5 litres Discuss
- 5. The ratio of water and alcohol in two different containers is 2:3 and 4:5. In what ratio we are required to mix the mixtures of two containers in order to get the new mixture in which the ratio of alcohol and water be 7:5?
Options- A. 7:3
- B. 5:3
- C. 8:5
- D. 2:7 Discuss
- 6. From a container of wine, a thief has stolen 15 liters of wine and replaced it with same quantity of water.He again repeated the same process. Thus in three attempts the ratio of wine and water became 343:169. The initial amount of wine in the container was:
Options- A. 75 liters
- B. 100 liters
- C. 150 liters
- D. 120 liters Discuss
- 7. A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ?
Options- A. 5:3
- B. 1:4
- C. 4:1
- D. 9:1 Discuss
- 8. From a container of wine, a thief has stolen 15 litres of wine and replaced it with same quantity of water. He again repeated the same process. Thus, in three attempts the ratio of wine and water became 343 : 169. The initial amount of wine in the container was:
Options- A. 75 litres
- B. 100 litres
- C. 150 litres
- D. 120 litres Discuss
- 9. A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?
Options- A. 58 l
- B. 65 l
- C. 50 l
- D. 62 l Discuss
- 10. In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm)
Options- A. 80%
- B. 70%
- C. 75%
- D. 62% Discuss
Alligation or Mixture problems
Search Results
Correct Answer: 91 liters
Explanation:
Milk Water
74% 26% (initially)
76% 24% ( after replacement)
Left amount = Initial amount
24 = 26
=> k = 91
Correct Answer: 22 lit
Explanation:
Let the capacity of the pot be 'P' litres.
Quantity of milk in the mixture before adding milk = 4/9 (P - 8)
After adding milk, quantity of milk in the mixture = 6/11 P.
6P/11 - 8 = 4/9(P - 8)
10P = 792 - 352 => P = 44.
The capacity of the pot is 44 liters.
Correct Answer: 15
Explanation:
Let quantity of mixture be x liters.
Suppose a container contains x units of liquid from which y units are taken out and replaced by Water. After operations , the quantity of pure liquid = units, Where n = no of operations .
So, Quantity of Milk =
Given that, Milk : Water = 9 : 16
=> Milk : (Milk + Water) = 9 : (9+16)
=> Milk : Mixture = 9 : 25
Therefore,
=> x = 15 liters
Correct Answer: 5 litres
Correct Answer: 5:3
Correct Answer: 120 liters
Explanation:
It means
Thus ,
=> K = 120
Thus the initial amount of wine was 120 liters.
Correct Answer: 9:1
Explanation:
Milk = 3/5 x 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 - 6 = 6 liters
Remaining water = 8 - 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed,
then amount of milk removed = 4/5 x 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 - 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
Now 10 lts milk is added => total milk = 18 lts
The required ratio of milk and water in the final mixture obtained
= (8 + 10):2 = 18:2 = 9:1.
Correct Answer: 120 litres
Explanation:
It means (since 343 + 169 = 512)
Thus,
Thus the initial amount of wine was 120 liters.
Correct Answer: 50 l
Explanation:
Let the tin contain 5x litres of liquids
=> 5(4x - 36) = 2(x + 36)
=> 20x - 180 = 2x + 72
=> x = 14 litres
Hence, the initial quantity of mixture = 70l
Quantity of liquid B
=
= 50 litres.
Correct Answer: 80%
Explanation:
Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm.
After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm.
So % of water = 100 x 60/75 = 80%.
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