Profit (%) = 9.09 % = 1/11
Since the ratio of water and milk is 1 : 11,
Therefore the ratio of water is to mixture = 1:12
Thus the quantity of water in mixture of 1 liter = 1000 x (1/12) = 83.33 ml
Amount of milk left after 3 operations
litres
Let quantity of mixture be x liters.
Suppose a container contains x units of liquid from which y units are taken out and replaced by Water. After operations , the quantity of pure liquid = units, Where n = no of operations .
So, Quantity of Milk =
Given that, Milk : Water = 9 : 16
=> Milk : (Milk + Water) = 9 : (9+16)
=> Milk : Mixture = 9 : 25
Therefore,
=> x = 15 liters
Let the capacity of the pot be 'P' litres.
Quantity of milk in the mixture before adding milk = 4/9 (P - 8)
After adding milk, quantity of milk in the mixture = 6/11 P.
6P/11 - 8 = 4/9(P - 8)
10P = 792 - 352 => P = 44.
The capacity of the pot is 44 liters.
Milk Water
74% 26% (initially)
76% 24% ( after replacement)
Left amount = Initial amount
24 = 26
=> k = 91
From the given data,
let the initial quantity of the mixture = 5x
Then,
Then the initial quantity of the mixture = 5x = 5 x 16 = 80 lit.
It means
Thus ,
=> K = 120
Thus the initial amount of wine was 120 liters.
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