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- Question
The letters of the word CASTIGATION is arranged in different ways randomly. What is the chance that vowels occupy the even places ?
Options- A. 0.04
- B. 0.043
- C. 0.047
- D. 0.05
- Correct Answer
- 0.043
ExplanationVowels are A I A I O,
C A S T I G A T I O N
(O) (E) (O) (E) (O) (E) (O) (E) (O) (E) (O)
So there are 5 even places in which five vowels can be arranged and in rest of 6 places 6 constants can be arranged as follows :
- 1. The day before yesterday, I was 25 years old, and next year I will turn 28. How is it possible?
Options- A. 31 Dec
- B. 30 Dec
- C. 1 Jan
- D. 28 Feb Discuss
- 2. A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning?
Options- A. 40
- B. 39
- C. 50
- D. 55 Discuss
- 3. The length of a side of an equilateral triangle is 8 cm. The area of the region lying between the circum circle and the incircle of the triangle is (use: ? = 22/7)
Options- A. 50 1/7 sq.cm
- B. 50 2/7 sq.cm
- C. 75 1/7 sq.cm
- D. 75 2/7 sq.cm Discuss
- 4. The sum of the length and breadth of a rectangle is 6 cm. A square is constructed such that one of its sides is equal to a diagonal of the rectangle. If the ratio of areas of the square and rectangle is 5 : 2, the area of the square in cm2 is
Options- A. 20
- B. 10
- C. 4?5
- D. 10?2 Discuss
- 5. From the four corners of a rectangular sheet of dimensions 25 cm x 20 cm, square of side 2 cm is cut off from four corners and a box is made. The volume of the box is
Options- A. 828 cm3
- B. 672 cm3
- C. 500 cm3
- D. 1000 cm3 Discuss
- 6. In a throw of a coin, find the probability of getting a head.
Options- A. 1
- B. 1/2
- C. 1/4
- D. 0.1 Discuss
- 7. A box contains 100 balls, numbered from 1 to 100. If three balls are selected at random and with replacement from the box, what is the probability that the sum of the three numbers on the balls selected from the box will be odd?
Options- A. 1/6
- B. 1/3
- C. 1/2
- D. 1/4 Discuss
- 8. A number is selected at random from the numbers 1 to 30. What is the probability that it is divisible by either 3 or 7 ?
Options- A. 1/30
- B. 2/30
- C. 1/25
- D. 1/2 Discuss
- 9. A fair coin is tossed 11 times. What is the probability that only the first two tosses will yield heads ?
Options- A. (1/2)^11
- B. (9)(1/2)
- C. (11C2)(1/2)^9
- D. (1/2) Discuss
- 10. One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn find the probability the card drawn is red.
Options- A. 2/3
- B. 1/2
- C. 1/52
- D. 13/51 Discuss
Probability problems
Search Results
Correct Answer: 31 Dec
Correct Answer: 39
Explanation:
Let the average after 17th innings = x
Then average after 16th innings = (x - 3)
Therefore 16 × (x - 3) + 87 = 17x
Therefore x = 39
Correct Answer: 50 2/7 sq.cm
Correct Answer: 20
Correct Answer: 1000 cm3
Correct Answer: 1/2
Explanation:
Here, s={H,T} and E={H}
P(E) = n(E)/n(S) = 1/2
Correct Answer: 1/2
Explanation:
P(odd) = P (even) = 1(because there are 50 odd and 50 even numbers)
Sum or the three numbers can be odd only under the following 4 scenarios:
Odd + Odd + Odd = =
Odd + Even + Even = =
Even + Odd + Even = =
Even + Even + Odd = =
Other combinations of odd and even will give even numbers.
Adding up the 4 scenarios above:
= + + + = =
Correct Answer: 1/30
Correct Answer: (1/2)^11
Explanation:
Probability of occurrence of an event,
P(E) = Number of favorable outcomes/Numeber of possible outcomes = n(E)/n(S)
? Probability of getting head in one coin = ½,
? Probability of not getting head in one coin = 1- ½ = ½,
Hence,
All the 11 tosses are independent of each other.
? Required probability of getting only 2 times heads =
Correct Answer: 1/2
Explanation:
We know that:
When one card is drawn from a pack of 52 cards
The numbers of possible outcomes n(s) = 52
We know that there are 26 red cards in the pack of 52 cards
? The numbers of favorable outcomes n(E) = 26
Probability of occurrence of an event: P(E)=Number of favorable outcomes/Numeber of possible outcomes=n(E)/n(S)
? required probability = 26/52 = 1/2.
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