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- Question
From the four corners of a rectangular sheet of dimensions 25 cm x 20 cm, square of side 2 cm is cut off from four corners and a box is made. The volume of the box is
Options- A. 828 cm3
- B. 672 cm3
- C. 500 cm3
- D. 1000 cm3
- Correct Answer
- 1000 cm3
- 1. The cost of levelling a circular field at 50 Paise per square metre is Rs 7700. The cost (in Rs) of putting up a fence all round it at Rs 1.20 per meter is ( Use ? = 22/7)
Options- A. Rs 132
- B. Rs 264
- C. Rs 528
- D. Rs 1056 Discuss
- 2. The area of a rhombus having one side 10 cm and one diagonal 12 cm is
Options- A. 48 cm2
- B. 96 cm2
- C. 144 cm2
- D. 192 cm2 Discuss
- 3. In a trapezium ABCD, AB and DC are parallel sides and ? ADC = 90°. If AB = 15 cm, CD = 40 cm and diagonal AC = 41 cm. Then the area of the trapezium ABCD is
Options- A. 245 cm2
- B. 240 cm2
- C. 247.5 cm2
- D. 250 cm2 Discuss
- 4. The radius of a sphere is 6 cm. It is melted and drawn into a wire of radius 0.2 cm. The length of the wire is
Options- A. 81 m
- B. 80 m
- C. 75 m
- D. 72 m Discuss
- 5. The radii of two concentric circles are 68 cm and 22 cm. The area of the closed figure bounded by the boundaries of the circles is
Options- A. 4140√ sq.cm.
- B. 4110√ sq.cm.
- C. 4080√ sq.cm.
- D. 4050√ sq.cm. Discuss
- 6. The sum of the length and breadth of a rectangle is 6 cm. A square is constructed such that one of its sides is equal to a diagonal of the rectangle. If the ratio of areas of the square and rectangle is 5 : 2, the area of the square in cm2 is
Options- A. 20
- B. 10
- C. 4?5
- D. 10?2 Discuss
- 7. The length of a side of an equilateral triangle is 8 cm. The area of the region lying between the circum circle and the incircle of the triangle is (use: ? = 22/7)
Options- A. 50 1/7 sq.cm
- B. 50 2/7 sq.cm
- C. 75 1/7 sq.cm
- D. 75 2/7 sq.cm Discuss
- 8. A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning?
Options- A. 40
- B. 39
- C. 50
- D. 55 Discuss
- 9. The day before yesterday, I was 25 years old, and next year I will turn 28. How is it possible?
Options- A. 31 Dec
- B. 30 Dec
- C. 1 Jan
- D. 28 Feb Discuss
- 10. The letters of the word CASTIGATION is arranged in different ways randomly. What is the chance that vowels occupy the even places ?
Options- A. 0.04
- B. 0.043
- C. 0.047
- D. 0.05 Discuss
Area problems
Search Results
Correct Answer: Rs 528
Correct Answer: 96 cm2
Correct Answer: 247.5 cm2
Correct Answer: 72 m
Correct Answer: 4140√ sq.cm.
Correct Answer: 20
Correct Answer: 50 2/7 sq.cm
Correct Answer: 39
Explanation:
Let the average after 17th innings = x
Then average after 16th innings = (x - 3)
Therefore 16 × (x - 3) + 87 = 17x
Therefore x = 39
Correct Answer: 31 Dec
Correct Answer: 0.043
Explanation:
Vowels are A I A I O,
C A S T I G A T I O N
(O) (E) (O) (E) (O) (E) (O) (E) (O) (E) (O)
So there are 5 even places in which five vowels can be arranged and in rest of 6 places 6 constants can be arranged as follows :
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