But at x=-1/3, log x is not defined.
The only admissible value of x is 1.
By trial and error method, when we substitute
x = 0
Both LHS and RHS are equal.
= log 1 + log 1 +.....+log 1
= 0.
Given equation 5x-17 = -x+7
Add 1x to each side of the equation
5x-17+x = -x+7+x
6x=24
x=4
Given
=> A
Therefore, A = B
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