= log 1 + log 1 +.....+log 1
= 0.
=
log (0.0000134). Since there are four zeros between the decimal point and
the first significant digit, the characteristic is ?5.
for (k,l) > 0 and k > l
Let k = x+1 and l = x
Therefore,
(x + 1) > x
Therefore,
By trial and error method, when we substitute
x = 0
Both LHS and RHS are equal.
But at x=-1/3, log x is not defined.
The only admissible value of x is 1.
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